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MAVERICK [17]
2 years ago
8

the ph of a naoh solution is 12.05. what is the concentration of [oh-] of the naoh solution? express your answer in standard not

ation
Chemistry
2 answers:
bagirrra123 [75]2 years ago
6 0

Answer:

0.0112

Explanation:

They said that was the answer.

Alborosie2 years ago
3 0

Answer:

0.01 M

Explanation:

NaOH (sodium hydroxide) is a strong base, so it is completely dissociated into ions in aqueous solution:

NaOH ⇄ Na⁺ + OH⁻

So, we have OH⁻ ions in solution.

From the problem, we have the pH value. The pH is calculated as:

pH = -log [H⁺]

As NaOH is a base, we can also calculate the pOH:

pOH = -log [OH⁻]

Thus. we can use the relation between pH and pOH to calculate the pOH and then use it to calculate [OH⁻]:

pH + pOH = 14 ⇒ pOH = 14 - pH = 14 - 12.05 = 1.95

pOH = -log [OH⁻] ⇒ [OH⁻] = 10^{-pOH}= 10^{1.95}= 0.0112 M ≅ 0.01 M

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The number of glyceraldehyde-3-phosphate molecules that would be produced from 24 turns of the calvin cycle would be
SVEN [57.7K]
The Calvin cycle, also called the light-independent or carbon fixation reactions, is the second stage of photosynthesis where water, and carbon dioxide (CO2) from air, are converted into organic compounds (i.e. sugars) using the energy from short-lived electronically excited carriers (ATP and NADPH) for the reactions. These organic compounds can then be used by the producing organism (i.e. plants) and the animals that feed on it. 

One product of the Calvin cycle is the glyceraldehyde-3-phosphate (G3P), which is later on used in the production of glucose and in the regeneration of <span>Ribulose 1,5-bisphosphate (RuBP), which is an organic compound</span> essential to the reactions in the cycle. 

One turn of Calvin Cycle produces 2 G3P molecules, each comprising of 3 carbons. This gives a total of 6 carbons. Five (5) of these carbons will be used to regenerate RuBP and only 1 will be available to form a surplus G3P later on. This surplus G3P will be used for the production of glucose (a 6-carbon sugar). 

Thus, 3 turns of the carbon cycle will produce 1 surplus G3P. There are 8 sets of 3-turns in 24 cycles, therefore, 

                       1 net G3P molecule * 8 sets of 3-turns  = 8 G3P molecules

Therefore, there are 8 net or surplus G3P molecules produced for 24 cycles of the Calvin Cycle. The total G3P molecules produced, including the ones that participated in the regeneration of RuBP would be 48 G3Ps. 

For every 3 turns, 6 G3P molecules are produced, 5 of which will be used in the regeneration of RuBP and 1 will be the net or surplus, to be used for the production of glucose. The 48 G3Ps then come from the calculation, 

                       6 total G3P molecules * 8 sets of 3-turns  = 48 G3P molecules


The figure below shows the products of the cycle after 3 turns (Source: https://ka-perseus-images.s3.amazonaws.com/2f4bdc8f8275834d3f5ef434d93bf16b991b2357.png). 

7 0
3 years ago
How many milliliters of water at 25.0°C with a density of 0.997 g/mL must be mixed with 163 mL of coffee at 97.9°C so that the r
Stolb23 [73]

Answer:

248 mL

Explanation:

According to the law of conservation of energy, the sum of the heat absorbed by water (Qw) and the heat released by the coffee (Qc) is zero.

Qw + Qc = 0

Qw = -Qc [1]

We can calculate each heat using the following expression.

Q = c × m × ΔT

where,

  • c: specific heat
  • m: mass
  • ΔT: change in the temperature

163 mL of coffee with a density of 0.997 g/mL have a mass of:

163 mL × 0.997 g/mL = 163 g

From [1]

Qw = -Qc

cw × mw × ΔTw = -cc × mc × ΔTc

mw × ΔTw = -mc × ΔTc

mw × (54.0°C-25.0°C) = -163 g × (54.0°C-97.9°C)

mw × 29.0°C = 163 g × 43.9°C

mw = 247 g

The volume corresponding to 247 g of water is:

247 g × (1 mL/0.997 g) = 248 mL

8 0
3 years ago
what happen when carbon dioxide is passed through water for short time and for long time?explain with chemical reaction.​
Delicious77 [7]

Answer:

Expert Verified

Explanation:

For short duration: ... When excess of carbon dioxide gas is passed through lime water then the white precipitate calcium carbonate formed first dissolves due to the formation of a soluble salt calcium hydrogen carbonate (Ca(HCO3)2, and the Solution becomes clear again

6 0
2 years ago
Hi! I'm on the last question of my homework and I'm stuck on it and was wondering if anyone could help me
Semmy [17]
I am not sure but this is what I think

This question uses the formula connecting mass, density and volume
Which is Density= Mass/Volume

Convert the mass in g
92.5 kg = 92,500g


7.87g/ml = 92,500/ Volume
Volume= 92,500/7.87
= 11,753.5 ml

Now since we have to give the answer in liters we can just divide by 1000 and get
11.75 litres

5 0
2 years ago
How do the two desalination processes differ from the atmospheric water generator in terms of where the processes can be used?
-Dominant- [34]

Water Desalination Processes. Water desalination processes separate dissolved salts and other minerals from water. Feedwater sources may include brackish, seawater, wells, surface (rivers and streams), wastewater, and industrial feed and process waters. Membrane separation requires driving forces including pressure (applied and vapor),...

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3 years ago
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