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MAVERICK [17]
2 years ago
8

the ph of a naoh solution is 12.05. what is the concentration of [oh-] of the naoh solution? express your answer in standard not

ation
Chemistry
2 answers:
bagirrra123 [75]2 years ago
6 0

Answer:

0.0112

Explanation:

They said that was the answer.

Alborosie2 years ago
3 0

Answer:

0.01 M

Explanation:

NaOH (sodium hydroxide) is a strong base, so it is completely dissociated into ions in aqueous solution:

NaOH ⇄ Na⁺ + OH⁻

So, we have OH⁻ ions in solution.

From the problem, we have the pH value. The pH is calculated as:

pH = -log [H⁺]

As NaOH is a base, we can also calculate the pOH:

pOH = -log [OH⁻]

Thus. we can use the relation between pH and pOH to calculate the pOH and then use it to calculate [OH⁻]:

pH + pOH = 14 ⇒ pOH = 14 - pH = 14 - 12.05 = 1.95

pOH = -log [OH⁻] ⇒ [OH⁻] = 10^{-pOH}= 10^{1.95}= 0.0112 M ≅ 0.01 M

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3 0
1 year ago
In the reaction FeCl2 + 2NaOH ->Fe(OH)2(s) + 2NaCl, if 6 moles of FeCl2 are added to 6 moles of Na0H, how many moles of NaOH
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Answer : The correct option is, (B) 6 mole

Explanation :

Given moles of FeCl_2 = 6 moles

Given moles of NaOH = 6 moles

First we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

FeCl_2+2NaOH\rightarrow Fe(OH)_2+2NaCl

From the given balanced reaction, we conclude that

As, 1 moles of FeCl_2 react with 2 moles of NaOH

So, 6 moles of FeCl_2 react with \frac{2}{1}\times 6=12 moles of NaOH

From this we conclude that, FeCl_2 is an excess reagent and NaOH is a limiting reagent because the given moles are less than the required moles and it limits the formation of product.

Thus, the number of moles of NaOH used up in the reaction = Required moles of NaOH - Given moles of NaOH

The number of moles of NaOH used up in the reaction = 12 - 6 = 6 moles

Therefore, the number of moles of NaOH used up in the reaction will be, 60 moles

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Explanation:

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