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Oduvanchick [21]
3 years ago
13

In a paragraph explain the "system of equations"​

Mathematics
1 answer:
MakcuM [25]3 years ago
4 0
A "system" of equations is a set or collection of equations that you deal with all together at once. Linear equations (ones that graph as straight lines) are simpler than non-linear equations, and the simplest linear system is one with two equations and two variables.
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Use a paragraph, flow chart, or two-column proof to prove the angle congruency. Given: ∠ CXY ≅ ∠ BXY
Llana [10]

Answer:

See explanation

Step-by-step explanation:

Consider triangles CAX and BAX. In these triangles,

  • \overline{AC}\cong \overline{AB} - given
  • \angle CAX\cong \angle BAX - given
  • \overline{AX}\cong \overline{AX} - reflexive property

By SAS postulate, \triangle CAX\cong \triangle BAX

Congruent triangles have conruent corresponding parts. So,

\overline{CX}\cong \overline{BX}

Consider triangles CXY and BXY. In these triangles,

  • \overline{CX}\cong \overline{BX} - proven
  • \angle CXY\cong \angle BXY - given
  • \overline{XY}\cong \overline{XY} - reflexive property

By SAS postulate, \triangle CXY\cong \triangle BXY

Congruent triangles have conruent corresponding parts. So,

\angle XCY\cong \angle XBY

5 0
3 years ago
Help me please thanks
kow [346]
Correct answer:
First reflect across the y-axis, then rotate 90 degrees clockwise about point K, then shift 3 units down.
6 0
3 years ago
Find the distance from P to l.
ki77a [65]
Equation\ of\ a\ line\ from\ 2\ points (x_1;\ y_1);\ (x_2;\ y_2):\\\\y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\(-4;\ 2)\ and\ (3;-5)\\subtitute:\\\\y-2=\dfrac{-5-2}{3-(-4)}\cdot(x-(-4))\\\\y-2=\dfrac{-7}{7}\cdot(x+4)\\\\y-2=-(x+4)\\\\y-2=-x-4\ \ \ |add\ x\ and\ 4\ to\ both\ sides\\\\x+y+2=0\\-------------------\\

Point-line\ distance\\l:Ax+By+C=0;\ (x_0;\ y_0)\\\\d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}\\\\x+y+2=0\to A=1;\ B=1;\ C=2\\(1;\ 2)\to x_0=1;\ y_0=2\\subtitute\\\\d=\dfrac{|1\cdot1+1\cdot2+2|}{\sqrt{1^2+1^2}}=\dfrac{|1+2+2|}{\sqrt2}=\dfrac{|5|}{\sqrt2}=\dfrac{5}{\sqrt2}=\dfrac{5\cdot\sqrt2}{\sqrt2\cdot\sqrt2}\\\\=\boxed{\dfrac{5\sqrt2}{2}}
4 0
3 years ago
The temperature at 6:00 P.M. was 68°F. This was 5°F lower than the temperature at 3:00 P.M. The temperature at 1:00 P.M. on that
bixtya [17]
76 degrees Fahrenheit
6 0
3 years ago
Read 2 more answers
What is the second step in sketching the graph of a rational function?
Elodia [21]

Answer:

C. Choosing test numbers to the left and right of each of the function's zeros and finding the value of the function at each test number

Step-by-step explanation:

Rational function: In mathematics, the term "rational function" is determined as any specific function that can be described through any "rational fraction", in other words, an algebraic fraction, involving both the denominator and the numerator are considered as polynomials. Therefore, the coefficients of specific polynomials are ought not to be in rational numbers and can be considered in the K field.

In the question above, the given statement represents option C is correct.

3 0
3 years ago
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