I assume that the parabola in this particular problem is one whose axis of symmetry is parallel to the y axis. The formula we're going to use in this case is (x-h)2=4p(y-k). We know variables h and k from the vertex (1,20) but p is not given. However, we can solve for p by substituting values x and y in the formula with the y-intercept:
(0-1)^2=4p(16-20)
Solving for p, p=-1/16.
Going back to the formula, we can finally solve for the x-intercepts. Simply fill in variables p, h and k then set y to zero:
(x-1)^2=4(-1/16)(0-20)
(x-1)^2=5
x-1=(+-)sqrt(5)
x=(+-)sqrt(5)+1
Here, we have two values of x
x=sqrt(5)+1 and
x=-sqrt(5)+1
thus, the answers are: (sqrt(5)+1,0) and (-sqrt(5)+1,0).
We will check if y and 60cm are parallel.
If the lengths 28cm, 56cm and 15cm, 30cm are in proportion, then y and the segment 60cm are parallel.
OK. We know: y and 60cm are parallel. Therefore we have equation:
<h3>Answer: y = 90 cm.</h3>
Answer:
-(x^2-2*x*3+3^2)+4=-x^2+6x-9+4=x^2+6x-5
Step-by-step explanation:
22.22222222222222 is the answer you can simplify it by saying 22.222...
4*25= 100 (total points)
x + y = 24 4x-2y = 66
since he only answered 24 questions
therefore max he can get is 96
x + y = 24
4x-2y = 66 from first equation,
y = 24-x plug that in second equation :
4x - 2(24-x) = 66
4x - 48 + 2x = 66
6x = 114
x = 19
