Answer
Step 1 and step 2
Step by step explanation
Heat can be transferred from one place to another place.
When pot kept on a stove, the heat from flame travels to the base of the pot, then heat travels from the base to the water.
Step 1: Heat from the flame travels to the base of the pot.
Step 2: Heat from the base of the pot travels to the water near its base.
Answer: C) Step 1 and Step 2
Answer:
y = 2
x = 5
Step-by-step explanation:
4x + 5y = 10 | ×3 |
3x - 3y = 21 | ×4 |
12x + 15y = 30
12x - 12y = 84
____________--
27y = -54
y = -54/27
y = 2
4x + 5y = 10 | ×3 |
3x - 3y = 21 | ×5 |
12x + 15y = 30
15x - 15y = 105
____________+
27x = 135
x = 135/27
x = 5
<h3>E
xplanation:</h3>
Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).
cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)
(1 -sin^2(θ))cot^2(θ) = . . . . . replace cos^2 with 1-sin^2
cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin
cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired
Answer:
its 11
Step-by-step explanation:
the mode is the difference between the highest and lowest date input
19-8=11
Answer:
-2n²
Step-by-step explanation:
Using the image attached:
We see that the second differences (blue ones) are all equal so we conclude that this is a quadratic sequence.
The quadratic sequence has the form:
To find the value of a we just divide second difference ( -4 ) by 2:
Now we have:
Substitute 
and 
into the equation above:
Since 
= -2 and 
= -8 , after simplification we have:
The solution of this system is:
The general term is :
