The food has 23629.64 cal
<h3>Further explanation</h3>
Given
mass = 1000 g of water
temperature increases 23.65 * C
Required
The energy of the food
Solution
Heat absorbed by water :
Q = m . c . Δt
Q = 1000 g x 4.184 J/g°C x 23.65 °C
Q = 98951.6 J
1 Joules = 0.2388 Calories
98951.6 J = 23629.64 cal
Not all matter in the reactant goes to the product. Some matter is byproducts.
If you are given the number of
moles of sodium bicarbonate, use the balanced chemical equation. The molar mass
of the acetic acid is 60 grams per mole. Using stochiometric balance.
Number of moles of acetic acid =
3 moles NaHCO3 (1 mol CH3COOH/1 mol NaHCO3) = 3 moles of acetic acid
Grams of acetic acid = 3 moles
of CH3COOH (60 g CH3COOH/1 mol CH3COOH) = <span>180 grams of acetic acid</span>
Answer:

Explanation:
You calculate the energy required to break all the bonds in the reactants.
Then you subtract the energy needed to break all the bonds in the products.
2H₂ + O₂ ⟶ 2H-O-H
Bonds: 2H-H 1O=O 4H-O
D/kJ·mol⁻¹: 436 498 464
