Answer:
Explanation:
you must be know the formula of potassium permaganate is KMnO₄
now you have already in question 2 things ,
1. the molarity of solution = 0.532 M
2. the mass of KMnO₄ = 2.99 g
the molarity law is M = moles of solute / volume (L)
so use this equation to calculate the volume in liter and convert the result to milliliter.
( if the mass unit is gram (g) = volume must be litter (L) and if the mass unit is milligram = volume must be milliliter (ml) )
** first you must use this equation to calculate how many moles do you have in KMnO₄
number of moles = mass (g) / molecular weight "MW" (g/mole )
now you have 2.99 g ( Mentioned in Question )
and you can calculate MW if you now the Chemical formula
so we have KMnO₄
Mw for KMnO₄ = 39 + 55 + 4x16 = 158 g/mole
**( K=39 , Mn=55 , O= 16 )
so number of moles = 2.99 / 158 = 0.018 = 0.02 moles
and if you go back to the molarity law :
Molarity = moles of solute / volume (L)
so 0.532 = 0.02 / volume (L)
Volume (L) = 0.532 x 0.02 = 0.01064 L
convert to ml = 0.01064 x 1000 = 10.64 ml
Good Luck
