Answer:
it is possible to remove 99.99% Cu2 by converting it to Cu(s)
Explanation:
So, from the question/problem above we are given the following ionic or REDOX equations of reactions;
Cu2+ + 2e- <--------------------------------------------------------------> Cu (s) Eo= 0.339 V
Sn2+ + 2e- <---------------------------------------------------------------> Sn (s) Eo= -0.141 V
In order to convert 99.99% Cu2 into Cu(s), the equation of reaction given below is needed:
Cu²⁺ + Sn ----------------------------------------------------------------------------> Cu + Sn²⁺.
Therefore, E°[overall] = 0.339 - [-0.141] = 0.48 V.
Therefore, the change in Gibbs' free energy, ΔG° = - nFE°. Where E° = O.48V, n= 2 and F = 96500 C.
Thus, ΔG° = - 92640.
This is less than zero[0]. Therefore, it is possible to remove 99.99% Cu2 by converting it to Cu(s) because the reaction is a spontaneous reaction.
(2) Mg, Ca, and Ba have the most similar chemical properties, and we know this because of their coexistence in the group alkali earth metals (group 2) on the periodic table.
Answer:
Atoms start out with the same number of negative charges (electrons), and positive charges (protons). ... Conversely, adding electrons to an atom would result in a negative ion. If you do this enough times, you can make an object positive or negative. Friction is one of the ways to separate charge.
Explanation:
Answer:
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Explanation:
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A solar cell has a similar function to a leaf.