Answer:
6.2 g
Explanation:
In a first-order decay, the formula for the amount remaining after <em>n</em> half-lives is
where
<em>N</em>₀ and <em>N</em> are the initial and final amounts of the substance
1. Calculate the <em>number of half-lives</em>.
If
2. Calculate the <em>final mass</em> of the substance.
Answer: B- a roll of photographic film
Explanation:
Founders education answer
Mitosis is a stage of the cell cycle
Answer:
The approximate molar mass of NaOH is 40 g/mol. You have 4 g NaOH.
No. of moles of NaOH is given by
n=(Given mass)/(Molar mass)
= 4/40 = 0.1 mol
1 mol has 6.022 × 10^23 molecules.
Thus, 0.1 mol has 6.022 × 10^23 × 0.1 molecules i.e. 6.022 × 10^22 molecules.
Explanation:
Answer:
a. Second order
b. First order
c. zero order
Explanation:
a. For a second order reaction,
As half life is inversely proportional to initial concentration, therefore, increase in intital concentration will decrease half life of the reaction.
b. First order reaction,
for first order reaction:
y = C + mx
Therefore, plot between ln A and t is a straight line.
c. For a zero order reaction,
Half life is proportional to initial concentration, therefore, increase in initial concentration will increase half life of the reaction.