it makes aloh
AlCl3 + 3NaOH = AlOH3 + 3NaCl
Al3+ + 3Cl- + 3Na+ + 3OH- = AlOH3 + 3Na+ + 3Cl-
all cancels out except
Al3+ + 3OH- = AlOH3
Answer:
The structure of the unknown compound is 2-butanol.
Explanation:
Chromic acid reagent is the most efficient procedure for oxidizing secondary alcohols. Chromic acid in aqueous sulfuric acid and acetone solution is known as Jones reagent, which oxidizes primary and secondary alcohols to carboxylic acids and ketones, respectively.
Lucas reagent reacts with primary, secondary and tertiary alcohols with fairly predictable rates, and these rates can be used to distinguish between the three types of alcohols. If the solution becomes cloudy in 3 to 5 minutes it indicates the presence of a secondary alcohol.
These two methods indicate the presence of a secondary alcohol, but the iodoform test indicates a specific structural unit.
Explanation:
To calculate that you need to know the value of the Kps (constant of solubility) at 30°C of KBr in water.
<u>When the product of the concentrations of both ions (Br- and K+) equals the Kps, the solution is saturated. </u>
Given the disociation of the salt in water:
The concentration of both ions are equal (1:1 ratio) and the same as the concentration of KBr added.
The Kps:
![Kps=[K^+][Br^-]](https://tex.z-dn.net/?f=Kps%3D%5BK%5E%2B%5D%5BBr%5E-%5D)
![[KBr]=(Kps)^{1/2}](https://tex.z-dn.net/?f=%5BKBr%5D%3D%28Kps%29%5E%7B1%2F2%7D)
[KBr] are <u>moles of the salt per litre of water</u>
Assuming a density of water of 1 g/cm3, 100 g are 0.1 litre
To calculate the mass:
![m=[KBr]*M*0.1 litre](https://tex.z-dn.net/?f=m%3D%5BKBr%5D%2AM%2A0.1%20litre)
where M is the molecular weight of the salt.
Answer:
What I came up with was D equaling out to be 42
Explanation:
Im assuming you just do the math
A. 3.5 x 104 = 364
B. 2.4 x 103 = 247.2
C. 1.4 x 10^2_2 = 280
D. 4.9 x 10-7 = 42
I hope I helped.
Answer:
8.324 Hope this helps! =)
