Answer:
see explanation
Step-by-step explanation:
Since the polynomial is of degree 6 , there will be 6 possible zeros, real or non- real.
Since non- real roots occur in conjugate pairs there will be an even amount.
Descartes' Rule of Signs
Given f(x) in standard form with descending powers of x then consider the signs of the coefficients.
The number of changes gives the maximum possible number of positive real zeros.
- / - / + / + ← has 1 sign change, thus 1 positive real zero
To determine the possible number of negative real zeros look at the coefficients of f(- x). This is the same as reversing the sign on terms of odd degree, that is
- / - / - / + ← has 1 sign change thus 1 negative real zero
Since there are 2 possible real zeros then there will be a possible
4 or 2 or 0 complex zeros
