Answer:
A hydraulic conductivity of 7.6 ft/day converts to 2.3 m/day.
Explanation:
This problem can be solved as a simple rule of three, with the mathematical conversion from feet to m.
Each ft has 0.3048m. So how many m are there in 7.6ft?
1 ft - 0.3048m
7.6ft - x m
So
A hydraulic conductivity of 7.6 ft/day converts to 2.3 m/day.
Answer:
The correct solution is Option d (when rocks develop joints or fractures
).
Explanation:
- Porosity is observable from descriptive samples taken. The drawbacks of receivable dams are that this is impossible to make true reflection temperature measurements, specific side-wall concrete samples while being often valuable can also result in poor coverage as well as dependence on log-derived porosity seems to have become the standard.
- As porosity rises, too much wind needs to pass further through most of the shelterbelt, which would be to say the less significant decrease in wind direction.
Some other available scenarios have no connexons with the particular circumstance. So this seems to be a reasonable option.
Answer:
Rita, or Mina are at fault.
Explanation:
