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Georgia [21]
3 years ago
11

Pls solve the 2nd q fast. Best answer will be marked brainliest

Mathematics
2 answers:
Sholpan [36]3 years ago
7 0
These are the answers in different forms

slega [8]3 years ago
4 0

Step-by-step explanation:

\frac{ - 16}{11}   +  \frac{ - 3}{9}  =  \frac{ - 48 - 11}{33} =  \frac{ - 59}{33}

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The long jump record, in feet, at a particular school can be modeled by f(x) = 19.6 + 2.5ln(x + 1) where x is the number of year
Sedbober [7]

Answer:

25.8

Step-by-step explanation:

6 0
4 years ago
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Paladinen [302]
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8 0
3 years ago
There are 32 girls and 18 boys in the chorus. what percent of the students in the chorus are girls?
klio [65]
So the total number of students is 50, and you want to find 32/50. and that is equal to 64%
7 0
3 years ago
Read 2 more answers
Please help! Its one of my last! Will give brainliest.
mixas84 [53]

Answer:

hexagon

Step-by-step explanation:

A hexagon has six vertices. Hope that this helps you and have a great day

7 0
4 years ago
Read 2 more answers
. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
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