3 years ago

Find the slope of a line given the following two points: (-1, 3) and (5, -2).

1 answer:

3 0

Your answer is B) -5/6.

We can find this using the formula (y2 - y1)/(x2 - x1) and substitute in the coordinates:

(-2 - 3)/(5 - -1) = -5/6

I hope this helps!

You might be interested in

Explain the process for finding the product of two integers

mafiozo [28]

Rule 1: The product of a positive integer and a negative integer is a negative integer. Rule 2: The product of two negative integers or two positive integers is a positive integer

4 0

3 years ago

Use implicit differentiation to find an equation of the tangent line to the curve at the given point.

andrew11 [14]

Differentiating both sides of

$x^2 + 2xy - y^2 + x = 20$

with respect to $x$ yields

$2x + 2y + 2x \dfrac{dy}{dx} - 2y \dfrac{dy}{dx} + 1 = 0 \\\\ \implies (2x-2y) \dfrac{dy}{dx} = -1 - 2x - 2y \\\\ \implies \dfrac{dy}{dx} = \dfrac{1 + 2x + 2y}{2(y-x)}$