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3 years ago

Find the slope of a line given the following two points: (-1, 3) and (5, -2).

1 answer:

3 0

Your answer is B) -5/6.

We can find this using the formula (y2 - y1)/(x2 - x1) and substitute in the coordinates:

(-2 - 3)/(5 - -1) = -5/6

I hope this helps!

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Which statement is true?

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Answer:

c ???

Step-by-step explanation:

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3 years ago

Read 2 more answers

Can someone help me with this

Nataly_w [17]

Answer:

b, e

Step-by-step explanation:

a, b) ordinarily, we claim the variable on the vertical axis is a function of the variable on the horizontal axis. By that claim, <em>temperature is a function of time</em>.

If the graph passed the horizontal line test (a horizontal line intersects in one place), then we could also say time is a function of temperature. The graph does not pass that test, so we cannot make that claim.

c) The graph has negative slope between 4:00 and 5:00. Temperature is decreasing in that interval, not increasing.

d) The graph has two intervals in which it is horizontal: 5:00-9:00 and 11:00-12:00. In those intervals it is neither increasing nor decreasing.

e) The graph shows a minimum in the interval 11:00-12:00. <em>The lowest temperature first occurs at 11:00</em>.

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3 years ago

Avery brought 1 gallons of sports drink for the track team to practice. How many pints is that amount?

Shkiper50 [21]

The amount will be 8 pints

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3 years ago

Which of these relations on {0, 1, 2, 3} are equivalence relations? Determine the properties of an equivalence re- lation that t

slava [35]

Answer:

The relations that are equivalence relations are a) and c)

Step-by-step explanation:

A relation on a set A is called an equivalence relation if it is reflexive, symmetric, and transitive

We are going to analyze each one.

a){ (0,0), (1,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

b){ (0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3) }

Is not an equivalence relation. Not reflexive: (1,1) is missing, not transitive: (0,2) and (2,3) are in the relation, but not (0,3)

c){ (0,0), (1,1), (1,2), (2,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

d){ (0,0), (1,1), (1,3), (2,2), (2,3), (3,1), (3,2) (3,3) }

Is not an equivalence relation. Not transitive: (1,3) and (3,2) are in the relation, but not (1,2)

e){ (0,0), (0,1) (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3) }

Is not an equivalence relation. Not symmetric: (1,2) is present, but not (2,1)Not transitive: (2,0) and (0,1) are in the relation, but not (2,1)

5 0

3 years ago

Which equation represents a circle that contains the point (-5, -3) and has a center at (-2, 1)?

Evgen [1.6K]

The equation (x + 2)² + (y - 1)² = 25 represents a circle that contain the point (-5 , -3) and has a center at (-2 , 1)

Step-by-step explanation:

The equation of a circle of center (h , k) and radius r is:

(x - h)² + (y - k)² = r²

The given is:

The center of the circle is (-2 , 1)
The circle passes through point (-5 , -3)

The length of the radius is the distance from the center of the circle

to a point on the circle

∵ The formula of the distance is $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

∵ The center of the circle is (-2 , 1)

∵ The circle passes through point (-5 , -3)

∴ $r=\sqrt{[(-5)-(-2)]^{2}+[(-3)-(1)]^{2}}$

∴ $r=\sqrt{[-3]^{2}+[-4]^{2}}$

∴ $r=\sqrt{9+16}$

∴ $r=\sqrt{25}$

∴ r = 5

∵ The equation of the circle is (x - h)² + (y - k)² = r²

∵ The center of the circle is (-2 , 1)

∴ h = -2 and k = 1

∵ r = 5

∴ r² = (5)² = 25

- Substitute the values of h , k , r² in the equation of the circle

∴ (x - -2)² + (y - 1)² = 25

∴ (x + 2)² + (y - 1)² = 25

The equation (x + 2)² + (y - 1)² = 25 represents a circle that contains

the point (-5 , -3) and has a center at (-2 , 1)

Learn more:

You can learn more about the equation of the circle in brainly.com/question/9510228

LearnwithBrainly

7 0

3 years ago