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Burka [1]
3 years ago
13

Evaluate the expression Numerical Answers Expected!

Mathematics
1 answer:
Klio2033 [76]3 years ago
3 0

Step-by-step explanation:

  1. First- 4
  2. {4}^{3}  = 4 \times 4 \times 4 = 64

7 - 3 = 4  \\ 4 \times 2 = 8

64 \div 8 = 8

8 final

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Factor the polynomial: 2x(x - 4) + 7 (x - 4)
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Step-by-step explanation:

With this question, we just have to group the terms, so in this case, we can remove the common term (x - 4), and then group the rest of them

If we do that we get:

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2 years ago
What is the solution to this system of equations?
Ede4ka [16]

Answer:

First choice.

Step-by-step explanation:

You could plug in the choices to see which would make all the 3 equations true.

Let's start with (x=2,y=-6,z=1):

2x+y-z=-3

2(2)+-6-1=-3

4-6-1=-3

-2-1=-3

-3=-3 is true so the first choice satisfies the first equation.

5x-2y+2z=24

5(2)-2(-6)+2(1)=24

10+12+2=24

24=24 is true so the first choice satisfies the second equation.

3x-z=5

3(2)-1=5

6-1=5

5=5 is true so the first choice satisfies the third equation.

We don't have to go any further since we found the solution.

---------Another way.

Multiply the first equation by 2 and add equation 1 and equation 2  together.

2(2x+y-z=-3)

4x+2y-2z=-6 is the first equation multiplied by 2.

5x-2y+2z=24

----------------------Add the equations together:

9x+0+0=18

9x=18

Divide both sides by 9:

x=18/9

x=2

Using the third equation along with x=2 we can find z.

3x-z=5 with x=2:

3(2)-z=5

6-z=5

Add z on both sides:

6=5+z

Subtract 5 on both sides:

1=z

Now using the first equation along with 2x+y-z=-3 with x=2 and z=1:

2(2)+y-1=-3

4+y-1=-3

3+y=-3

Subtract 3 on both sides:

y=-6

So the solution is (x=2,y=-6,z=1).

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3 years ago
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