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AleksandrR [38]
3 years ago
6

Helpppppp....... 75 points givin

Mathematics
2 answers:
zavuch27 [327]3 years ago
7 0

Answer:

65 4 67. 1.23 A histogram (using the classes 10–14, 15–19, 20–24, etc.) is ... fairly symmetric with center around 2% to 3%, spread from −14.7% to 19.2%. (c) ... (b) Below. (c) The distribution is skewed to the left, with center (median) around 7.8. ... Using table values: 1.45 ± 1.96(0.40) = 1.45 ± 0.784, or 0.666 to 2.234 grams.

VMariaS [17]3 years ago
3 0

Answer:

Step-by-step explanation:

I believe it is C

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Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi
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Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

The formula to compute covariance is:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

The formula to compute the variances are:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}

Consider the table attached below.

Compute the covariance as follows:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

                 =(5\times 165)-(30\times 25)\\=75

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50

Compute the correlation coefficient as follows:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

            =\frac{75}{\sqrt{230\times 50}}

            =0.69937\\\approx0.70

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0
3 years ago
The length of a rectangle is fourteen less than two and a half times its width. The perimeter of the
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Answer:

Step-by-step solution:

8 0
4 years ago
Li Na is going to plant 6363 63 tomato plants and 8181 81 rhubarb plants. Li Na would like to plant the plants in rows where eac
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Answer: The greatest number of rows Li Na can plant is 9.


Step-by-step explanation:

Given: Li Na is going to plant 63 tomato plants and 81 rhubarb plants.

Li Na would like to plant the plants in rows where each row has the same number of tomato plants and each row has the same number of rhubarb plants.

To find the greatest number of rows Li Na can plant, we need to find the GCF of 63 and 81.

Since , 63=7\times9\ and\ 81=8\times9

Clearly, GCF(63,81)=9

Therefore, the greatest number of rows Li Na can plant is 9.

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Type the correct answer in the box.
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Answer:

en español porfa no ablo ingles

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