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umka2103 [35]
3 years ago
13

The rate of evaporation of water does not depend on the​

Chemistry
2 answers:
Fynjy0 [20]3 years ago
6 0

Answer:

The rate of evaporation of water does not depend on the Size of vessel

riadik2000 [5.3K]3 years ago
5 0

Explanation:

The rate of evaporation does not depend on the type of particles because it completely depends upon the surface area of the liquid, if surface area is large evaporation will be maximum. Evaporation also depends upon wind speed, if the wind is flowing at a higher speed, then the rate of evaporation increases. Same will be applied in the case of humidity.

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What is the oxidation number of S In Li2SO4? <br><br>A. +1<br>B. +2<br>C. +5<br>D. +6​
-Dominant- [34]

Answer:

6

Explanation:

Li has an oxydation number of 1          2*1     = 2

O has an oxidation number of -2         4(-2) = -8

S has an oxydation number of x           1 * x = x

The oxidation number on the molecule is 0.

So here is the equation

2 - 8 + x = 0        Combine like terms

-6 + x = 0            Add 6 to both sides

-6 + 6 + x = 6      Combine like terms

x = 6

Sulphur in this case has an oxidation number of 6

3 0
3 years ago
Foliated rocks are distinguished by ____.
kenny6666 [7]
Foliated rocks are distinguished by layers, banding, or flakiness. Foliated rocks are given names depending their mineralogy and texture. These names can be slate, Phyllite and Schist. These rocks are formed within the Earth's interior under extremely high pressures that are unequal. 
3 0
3 years ago
Read 2 more answers
A chemist needs 10 liters of a 25% acid solution. The solution is to be mixed from three solutions whose concentrations are 10%,
mojhsa [17]

Answer:

a) 1 litre of  10% solution and 7 litre of 20% solution

b) 1.67 litres of 50% solution and 8.33 litres of the 20% solution

c) 3.75 litres of 50% solution and 6.25 litres of 20% solution

Explanation:

Given:

chemist needs = 10 liters of a 25% acid solution

Concentration of three solutions that are to be mixed = 10%, 20% and 50%.

Solution:

A) Use 2 liters of the 50% solution

Let us mix this with 10% and 20% solution

They will have to equal 8 litres

Let x=20% solution

Then (8-x) =10%

So the equation becomes,

10%(8-x)+ 20%x+50%(2)=25(10)

(0.1)(8-x) +0.2x+0.50(2)= 0.25(10)

0.8-0.1x+0.2x+1.0=2.5

0.2x-0.1x=2.5-0.8-1.0

0.1x=0.7

x=\frac{0.7}{0.1}

x= 7

so, 8-x = 8 -7= 1 litre of  10% solution and 7 litre of 20% solution

B)Use as little as possible of the 50% solution

Let x be the amount of 50% solution.

Then(10-x) be the 20% solution

Now the equation becomes,

50%(x)+20%(10-x)=25%(10)

0.50x+0.2(10-x)=0.25(10)

0.5x+2.0-0.2x=2.5

0.3x=2.5-2.0

0.3x=0.5

x=\frac{0.5}{0.3}

x=1.67  

now (10-x)=(10-1.67)=8.33

so there will be 1.67 litres of 50% solution and 8.33 litres of the 20% solution

c) ) Use as much as possible of the 50% solution

Let x be the amount of 50% solution.

Then(10-x) be the 20% solution

Now the equation becomes,

50%(x)+10%(10-x)=25%(10)

0.50x+0.1(10-x)=0.25(10)

0.5x+1.0-0.1x=2.5

0.4x=2.5-1.0

0.4x=1.5

x=\frac{1.5}{0.3}

x=3.75

Now, (10-x)=(10- 3.75)=6.26

So there will be 3.75 litres of 50% solution and 6.25 litres of 20% solution

5 0
3 years ago
Why does the ice melt when you hold it in your hand? A.Heat is transferred from your hand to the ice cube. B.Heat from the ice c
Thepotemich [5.8K]
A. Heat is transferred from your hand to the ice cube.
3 0
3 years ago
A mysterious white powder could be powdered sugar (C12H22O11), cocaine (C17H21NO4), codeine (C18H21NO3), norfenefrine (C8H11NO2)
konstantin123 [22]

Answer: norfenefrine (C_8H_{11}NO_2)

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(-114.6-(-115.5)^0C=0.9^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

K_f = freezing point constant = 1.99^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}

Weight of solvent (ethanol)= density\times volume=0.789g/cm^3\times 1.50cm^3=1.18g=1.18\times 10^{-3}kg

Molar mass of unknown non electrolyte = M g/mol

Mass of unknown non electrolyte added = 82 mg = 0.082 g (1g=1000mg)

0.9=1\times 1.99\times \frac{0.082g}{M g/mol\times 1.18\times 10^{-3}}kg}

M=154g/mol

The molecular mass of norfenefrine (C_8H_{11}NO_2) is near to 154 and thus the identity of the white powder is norfenefrine .

4 0
3 years ago
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