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barxatty [35]
3 years ago
13

Why can't anything cheer me up rn?... :'(

Chemistry
2 answers:
Kruka [31]3 years ago
7 0

not sure.. you should eat poptarts

Murljashka [212]3 years ago
5 0

Answer:

well if u need some one i'm here

Explanation:

...

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You shake a can of soda and open it, which cause the pressure to decrease. what happens to the volume of the CO2. the soda​
navik [9.2K]

Answer: <em>When you take the top off of a bottle of soda, the pressure inside the bottle decreases and goes to the same pressure as the atmosphere. When that happens the carbon dioxide inside is no longer forced to be a liquid and turns back into a gas, causing the bubbles that we're so familiar with.</em>

Explanation:

However, producing foaming carbon dioxide gas by shaking a bottle of soda water is a physical change, while producing foaming carbon dioxide gas by combining baking soda and vinegar is a chemical change. ... Because no chemical bonds are broken and no new molecules are formed, this is a physical change in the system.

4 0
3 years ago
A bond where electrons are transferred from a cation to an anion is called a (n) ___________bond.\
emmasim [6.3K]
When elements transfer electrons from a cation and an anion it called ionic bond.
6 0
3 years ago
What are deltaTb and deltaTf for an aqueous solution that is 1.5g nacl in 0.250kg h2o? Given Kb=0.51 C/m and kr=1.86 C/m
bulgar [2K]

Answer:

T_f for given question is 2.79 and T_b is 0.52

\Delta T_b = I \times K_b \times m {i- vant hoff’s constant ; Kb- constant ; m molarity }

M = no. of moles of the solute present in one kg of solution

Let the weight of amount of solute be “w” and its molecular mass be “M”

Let the mass of the solvent in the given question be “x”

\Delta T_b = I \times K_b \times (w/M)/ x

\Delta T_b = I \times K_b \times w/Mx

\Delta T_b = 1 \times 0.51 \times1.5/(0.250 \times 58.44) = 0.052

\Delta T_f = M \times K_f = 1.86 \times 1.5 = 2.79

4 0
3 years ago
Calculate the value of the equilibrium constant, Kc , for the equilibrium shown below, if 0.124 moles of NO, 0.0240 mole of H2,
sdas [7]

the reaction is

2NO(g) + 2H2(g) <—> N2(g) + 2H2O (g)

Kc = [N2] [ H2O]^2 / [NO]^2 [ H2]^2

Given

moles of NO = 0.124 therefore [NO] = moles /volume = 0.124 /2 = 0.062

moles of H2 = 0.0240 , therefore [H2] = moles / volume = 0.0240 / 2 = 0.012

moles of N2 = 0.0380 , therefore [N2] = moles / volume = 0.0380 / 2 = 0.019

moles of H2O  = 0.0276 , therefore [H2O] = moles / volume = 0.0276 / 2 = 0.0138

Kc = (0.019) ( 0.0138)^2 / (0.062)^2 ( 0.012)^2 = 6.54



4 0
3 years ago
I need your help!! about Chemistry (15 point!!)
irakobra [83]
1. I think it is true?
2. Low melting points
3. True
4. Atomic number, I think it’s periods?
5. Groups?


Sorry, I might not get all of them right :(


Hope this helps you in any way!!
6 0
3 years ago
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