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3 years ago

What precipate forms when you mix lead (II) nitrate with potassium chloride?

Chemistry

1 answer:

SSSSS [86.1K]3 years ago

4 0

Answer:

As soon as Ag(+) comes in contact with Cl(-)we form a precipitate of AgCl.

Hope this helps!

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How does tension affect the speed of a wave in a rope

Ainat [17]

Hi sorry

I don’t know

but maybe next time

3 0

2 years ago

When 1.2383 g of an organic iron compound containing Fe, C, H, and O was burned in O2, 2.3162 g of CO2 and 0.66285 g of H2O were

uysha [10]

Answer:

$\boxed{\text{C$_{15}$H$_{21}$FeO$_{6}$}}$

Explanation:

Let's call the unknown compound X.

1. Calculate the mass of each element in 1.23383 g of X.

(a) Mass of C

$\text{Mass of C} = \text{2.3162 g } \text{CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{0.632 07 g C}$

(b) Mass of H

$\text{Mass of H} = \text{0.66285 g }\text{H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g } \text{{H$_{2}$O}}} = \text{0.074 157 g H}$

(c)Mass of Fe

(i)In 0.4131g of X

$\text{Mass of Fe} = \text{0.093 33 g Fe$_{2}$O$_{3}$}\times \dfrac{\text{111.69 g Fe}}{\text{159.69 g g Fe$_{2}$O$_{3}$}} = \text{0.065 277 g Fe}$

(ii) In 1.2383 g of X

$\text{Mass of Fe} = \text{0.065277 g Fe}\times \dfrac{1.2383}{0.4131} = \text{0.195 67 g Fe}$

(d)Mass of O

Mass of O = 1.2383 - 0.632 07 - 0.074 157 - 0.195 67 = 0.336 40 g

2. Calculate the moles of each element

$\text{Moles of C = 0.63207 g C}\times\dfrac{\text{1 mol C}}{\text{12.01 g C }} = \text{0.052 629 mol C}\\\\\text{Moles of H = 0.074157 g H} \times \dfrac{\text{1 mol H}}{\text{1.008 g H}} = \text{0.073 568 mol H}\\\\\text{Moles of Fe = 0.195 67 g Fe} \times \dfrac{\text{1 mol Fe}}{\text{55.845 g Fe}} = \text{0.003 5038 mol Fe}\\\\\text{Moles of O = 0.336 40} \times \dfrac{\text{1 mol O}}{\text{16.00 g O}} = \text{0.021 025 mol O}$

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

$\text{C: } \dfrac{0.052629}{0.003 5038}= 15.021\\\\\text{H: } \dfrac{0.073568}{0.003 5038} = 20.997\\\\\text{Fe: } \dfrac{0.003 5038}{0.003 5038} = 1\\\\\text{O: } \dfrac{0.021025}{0.003 5038} = 6.0006$

4. Round the ratios to the nearest integer

C:H:O:Fe = 15:21:1:6

5. Write the empirical formula

$\text{The empirical formula is } \boxed{\textbf{C$_{15}$H$_{21}$FeO$_{6}$}}$

5 0

3 years ago

What mass of oxygen would form from 2.0 moles of water

kicyunya [14]

The reaction of the decomposition of water into oxygen gas and hydrogen is balanced as such:

$2H_{2} O -> 2H_{2} + O_{2}$

Using conversion factors, 2.0 mol H2O is equivalent to 1 mol O2, as per the reaction.

1 mol O2 is equivalent to 32g O2 (1 mol O2 * $\frac{32 g O2}{1molO2}$ )

Answer: 32 g of oxygen.

7 0

3 years ago

A board of wood has a density of 0.487 g/cm3. The board is measured to have a length of 3.21 cm, a width of 12.2 cm and a height

ivolga24 [154]

Answer:

The mass of board is 1.52 g.

Explanation:

Given data:

Density of wood = 0.487 g/cm³

Length of board = 3.21 cm

Width of board = 12.2 cm

Height of board = 0.80 mm (0.80/10=0.08 cm)

Mass of board = ?

Solution:

We know that density of an object is equal to the mass of substance divided by its volume. So we can calculate the mass from density formula.

Formula:

D = m/v

d = density

m = mass

v = volume

Now we will calculate the volume first.

V = length × width × height

V = 3.21 cm × 12.2 cm × 0.08 cm

V = 3.13cm³

Now we will calculate the mass.

D = m/v

0.487 g/cm³ = m/ 3.13 cm³

m = 0.487 g/cm³ × 3.13 cm³

m = 1.52 g

The mass of board is 1.52 g.

5 0

3 years ago

What two trends are commonly seen in modern monthly co2 concentration charts??

Nataliya [291]

The 2 trends that are commonly seen in modern concentration chart , first it is increasing. Since the star of industrial revolution the amount of co2 increases with time. The second trend is that the temperature also increases because it is a green house gas which causes the global warming.

7 0

3 years ago