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Neko [114]
3 years ago
14

Mg(s)+2HCl(aq)  →  MgCl2(aq)+H2(g)

Chemistry
1 answer:
Rama09 [41]3 years ago
8 0

Answer:

Mg(s)+2H^+(aq)\rightarrow Mg^{2+}(aq)+H_2(g)

Explanation:

Hello!

In this case, since the writing of a net ionic equation first implies writing the complete molecular equation:

Mg(s)+2HCl(aq) \rightarrow MgCl_2(aq)+H_2(g)

We can see that HCl and MgCl2 are ionized because they are aqueous, thus we write:

Mg(s)+2H^+(aq)+2Cl^-(aq) \rightarrow Mg^{2+}(aq)+2Cl^-(aq)+H_2(g)

In such a way, we can cancel out the chloride ions as they are the spectator ones to obtain the net ionic one:

Mg(s)+2H^+(aq)\rightarrow Mg^{2+}(aq)+H_2(g)

Best regards!

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4 0
3 years ago
Iodine pentafluoride reacts slowly with glass and violently with water. determine its molecular mass.
pickupchik [31]
<h3>Answer:</h3>

               221.90 g.mol⁻¹

<h3>Explanation:</h3>

                          The mass of contained by a molecule is known as molecular mass. It is the sum of atomic weights of the elements contained by the molecule. In given case Iodine Pentafluoride has a chemical formula,

                                                          IF₅

The atomic weights of each element are as;

                                        Iodine  =  126.90 g.mol⁻¹

                                        Fluorine  =  19.00 g.mol⁻¹

As there are five atoms of Fluorine so, we will multiply the atomic weight of Fluorine by five and that of Iodine by one as there is only one Iodine atom.

Therefore,

         Molecular Mass of IF₅  =  (1 × 126.90 g.mol⁻¹) + (5 × 19.00 g.mol⁻¹)

         Molecular Mass of IF₅  =  (126.90 g.mol⁻¹) + (95.00 g.mol⁻¹)

         Molecular Mass of IF₅  =  221.90 g.mol⁻¹

8 0
4 years ago
PLEASE HELP!!!
Kaylis [27]
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8 0
3 years ago
Balanced equation for formation of potassium suberate from cyclooctene
hjlf

The balanced equations for the  formation of potassium suberate from cyclooctene are;

3KMnO4 + 3C8H18 + 4H2O --> 3C8H17(OH)2 + 2MnO2 + 2KOH and

3C8H14(OH)2 +  6KMnO4 ----> 3KCOO(CH2)6 COOK + 6MnO2 + 6H20

<h3>What is potassium suberate ?</h3>

The compound potassium suberate  is obtained from cyclooctene. The first step in the process is the oxidation of cyclooctene using potassium permanganate as follows;

3KMnO4 + 3C8H18 + 4H2O --> 3C8H17(OH)2 + 2MnO2 + 2KOH

This is followed by the production of potassium suberate from the reaction equation;

3C8H14(OH)2 +  6KMnO4 ----> 3KCOO(CH2)6 COOK + 6MnO2 + 6H20

Learn more about potassium suberate: brainly.com/question/8507057?

5 0
2 years ago
Based on the following equation, how many moles of hydrochloric acid (HCl)are needed to react with 0.44 moles of potassium
inysia [295]

Answer:

1.76 moles of HCl.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KMnO₄ + 8HCl —> 3Cl₂ + 2MnO₂ + 4H₂O + 2KCl

From the balanced equation above,

2 moles of KMnO₄ reacted with 8 moles of HCl.

Finally, we shall determine the number of mole of HCl needed to react with 0.44 moles of KMnO₄. This can be obtained as follow:

From the balanced equation above,

2 moles of KMnO₄ reacted with 8 moles of HCl.

Therefore, 0.44 moles of KMnO₄ will react with = (0.44 × 8)/2 = 1.76 moles of HCl.

Thus, 1.76 moles of HCl is needed for the reaction.

5 0
3 years ago
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