mechanical waves are classified by how they move. there are two types of mechanical waves:transverse waves and longitudinal waves.
<h3>Answer:</h3>
221.90 g.mol⁻¹
<h3>Explanation:</h3>
The mass of contained by a molecule is known as molecular mass. It is the sum of atomic weights of the elements contained by the molecule. In given case Iodine Pentafluoride has a chemical formula,
IF₅
The atomic weights of each element are as;
Iodine = 126.90 g.mol⁻¹
Fluorine = 19.00 g.mol⁻¹
As there are five atoms of Fluorine so, we will multiply the atomic weight of Fluorine by five and that of Iodine by one as there is only one Iodine atom.
Therefore,
Molecular Mass of IF₅ = (1 × 126.90 g.mol⁻¹) + (5 × 19.00 g.mol⁻¹)
Molecular Mass of IF₅ = (126.90 g.mol⁻¹) + (95.00 g.mol⁻¹)
Molecular Mass of IF₅ = 221.90 g.mol⁻¹
I think it comes from Fungi. I'm not 100% sure about that though.
The balanced equations for the formation of potassium suberate from cyclooctene are;
3KMnO4 + 3C8H18 + 4H2O --> 3C8H17(OH)2 + 2MnO2 + 2KOH and
3C8H14(OH)2 + 6KMnO4 ----> 3KCOO(CH2)6 COOK + 6MnO2 + 6H20
<h3>What is potassium suberate ?</h3>
The compound potassium suberate is obtained from cyclooctene. The first step in the process is the oxidation of cyclooctene using potassium permanganate as follows;
3KMnO4 + 3C8H18 + 4H2O --> 3C8H17(OH)2 + 2MnO2 + 2KOH
This is followed by the production of potassium suberate from the reaction equation;
3C8H14(OH)2 + 6KMnO4 ----> 3KCOO(CH2)6 COOK + 6MnO2 + 6H20
Learn more about potassium suberate: brainly.com/question/8507057?
Answer:
1.76 moles of HCl.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2KMnO₄ + 8HCl —> 3Cl₂ + 2MnO₂ + 4H₂O + 2KCl
From the balanced equation above,
2 moles of KMnO₄ reacted with 8 moles of HCl.
Finally, we shall determine the number of mole of HCl needed to react with 0.44 moles of KMnO₄. This can be obtained as follow:
From the balanced equation above,
2 moles of KMnO₄ reacted with 8 moles of HCl.
Therefore, 0.44 moles of KMnO₄ will react with = (0.44 × 8)/2 = 1.76 moles of HCl.
Thus, 1.76 moles of HCl is needed for the reaction.