Answer: The equation is y = -6*x
Step-by-step explanation:
I suppose that we want to find the equation for a line that passes through the point (-1, 6) and the origin (remember that the origin is the point (0,0))
A general linear equation is written as:
y = a*x + b
Where a is the slope and b is the y-intercept.
If this line passes through the points (x₁, y₁) and (x₂, y₂), then the slope of the line is equal to:
a = (y₂ - y₁)/(x₂ - x₁)
Now we know that our line passes through the points (0, 0) and (-1, 6), then the slope is:
a = (6 - 0)/(-1 - 0) = 6/-1 = -6
Then our equation is something like:
y = -6*x + b
To find the value of b we can use the fact that this line passes through the point (0, 0).
This means that when x = 0, y is also equal to zero.
If we replace these values in the equation we get:
0 = -6*0 + b
0 = b
Then our equation is:
y = -6*x
Assuming that the triangle is a right triangle, we can reverse engineer the Pythagorean theorem (a^2+b^2=c^2).
60^2 + x^2 = 61^2
3600 + x^2 = 3721
x^2 = 3600 - 3721
x^2 = 121
x = sqrt121
x = 11
Answer:
Case A) tau_net = -243.36 N m, case B) tau_net = 783.36 N / m, tau_net = -63.36 N m, case C) tau _net = - 963.36 N m,
Explanation:
For this exercise we use Newton's relation for rotation
Σ τ = I α
In this exercise the mass of the child is m = 28.8, assuming x = 1.5 m, the force applied by the man is F = 180N
we will assume that the counterclockwise turns are positive.
case a
tau_net = m g x - F x2
tau_nett = -28.8 9.8 1.5 + 180 1
tau_net = -243.36 N m
in this case the man's force is downward and the system rotates clockwise
case b
2 force clockwise, the direction of
the force is up
tau_nett = -28.8 9.8 1.5 - 180 2
tau_net = 783.36 N / m
in case the force is applied upwards
3) counterclockwise
tau_nett = -28.8 9.8 1.5 + 180 2
tau_net = -63.36 N m
system rotates clockwise
case c
2 schedule
tau_nett = -28.8 9.8 1.5 - 180 3
tau _net = - 963.36 N m
3 counterclockwise
tau_nett = -28.8 9.8 1.5 + 180 3
tau_net = 116.64 Nm
the sitam rotated counterclockwise
<h3><u><em>
Cr: moya1316</em></u></h3>
hookes law gives the equation F=kx where F is the elastic force and k is the constant and x or small e is extension if we draw a graph you'll see that the graph increases by the same ratio every single time hence giving a straight line show that they are F and x are propotional to a certain limit
