The answer is the third one because the animal died before the rock was there
Answer: The gas occupies a space of 5.57 L at 26 Celsius and 101.75 kPa.
Explanation:
Given: Mass = 26 g
Pressure = 101.75 kPa
Convert kPa into atm as follows.
Temperature =
Now, moles of a substance is defined as mass of substance divided by its molar mass.
As molar mass of 2,2 dimethyl hexane is 114.23 g/mol. So, its number of moles are calculated as follows.
Formula used to calculate the volume is as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
Thus, we can conclude that the gas occupies a space of 5.57 L at 26 Celsius and 101.75 kPa.
Answer : The concentration of and at equilibrium is, 0.0031 M and 0.0741 M respectively.
Explanation : Given,
Moles of = 0.166 mol
Volume of solution = 2.15 L
First we have to calculate the concentration of
Now we have to calculate the concentration of and at equilibrium.
Initial conc. 0.0772 0 0
At eqm. 0.0772-x x x
The expression for equilibrium constant is:
By solving the term, we get the value of 'x'.
x = 0.0741
Thus,
The concentration of at equilibrium = (0.0772-x) = (0.0772-0.0741) = 0.0031 M
The concentration of at equilibrium = x = 0.0741 M
Answer:
The correct answer is option C.
Explanation:
r = resultant vector
y = vertical component of vector
x = horizontal component of vector
We have :
The vertical component of a vector is 40 N and its horizontal component is 25 N.
x = 25 N
y = 40 N
47.2 N is the magnitude of the vector.