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sdas [7]
4 years ago
11

How many grams of Chloride are in 760 grams of Iron (III) Chloride

Chemistry
1 answer:
Ede4ka [16]4 years ago
8 0
Do you have a balanced equation with this as well?

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How many moles of solute are contained in 200 milliliters of a 1 M solution?
lorasvet [3.4K]
The answer is (2) 0.2. The unit of M means 1 mol/L. The conversion of liter and milliliter is 1 liter equals 1000 milliliters. So the molar number of solute is 1*0.2=0.2 mol.
5 0
4 years ago
PLEASE HELP I DONT UNDERSTAND A THING
Ymorist [56]

Answer:

I and III

Explanation:

6 0
3 years ago
Which one of the following compounds utilizes both ionic and covalent bonding?A) C6H12O6.B) CC32-.C) CO2.D) MgCl2.E) Al2(SO4)3.
JulsSmile [24]

Answer:

Al2(SO4)3

Explanation:

Looking at this carefully, we will discover that Al2(SO4)3 is composed of Al^3+ and SO4^2-.

The aluminum and sulphate ions are ionically bonded. However, the oxygen and sulphur in the sulphate ion are covalently bonded.

Hence, Al2(SO4)3 contains both ionic and covalent bond.

8 0
3 years ago
Please help me..<br>what is carbon 1/12​
tatuchka [14]

Answer:

It is expressed as a multiple of one-twelfth the mass of the carbon-12 atom, 1.992646547 × 10−23 gram, which is assigned an atomic mass of 12 units. ... In this scale 1 atomic mass unit (amu) corresponds to 1.660539040 × 10−24 gram.

6 0
3 years ago
Magnesium metal (0.100 mol) and a volume of aqueous hydrochloric acid that contains 0.500 mol of HCl are combined and react to c
jok3333 [9.3K]

Answer:

2.24 L of hydrogen gas, measured at STP, are produced.

Explanation:

Given, Moles of magnesium metal, Mg = 0.100 mol

Moles of hydrochloric acid, HCl = 0.500 mol

According to the reaction shown below:-

Mg_{(s)} + 2HCl_{(aq)}\rightarrow MgCl_2_{(aq)} + H_2_{(g)}

1 mole of Mg reacts with 2 moles of HCl

0.100 mol of Mg reacts with 2*0.100 mol of HCl

Moles of HCl must react = 0.200 mol

Available moles of HCl = 0.500 moles

Limiting reagent is the one which is present in small amount. Thus, Mg is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of Mg on reaction forms 1 mole of H_2

0.100 mole of Mg on reaction forms 0.100 mole of H_2

Mole of H_2 = 0.100 mol

At STP,  

Pressure = 1 atm  

Temperature = 273.15 K

Volume = ?

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V L = 0.100 × 0.0821 L.atm/K.mol × 273.15 K  

<u>⇒V = 2.24 L</u>

2.24 L of hydrogen gas, measured at STP, are produced.

4 0
3 years ago
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