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3 years ago

How many grams of Chloride are in 760 grams of Iron (III) Chloride

Chemistry

1 answer:

Ede4ka [16]3 years ago

8 0

Do you have a balanced equation with this as well?

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150.0 grams of iron at 95.0 °C, is placed in an insulated container containing 500.0 grams of water. The temperature of the wate

Lorico [155]

Explanation:

in it I mass=150g,initial temp 1=95,mass2=500g,temp2=?,final temperature=27.2 C1=0.444C2=4.18

using formula

m1c1(final temp-initial temp1) =m2c2(temp2-final temp)

150x0.444(27.2-95)=500x4.18(?-27.2)

66(-67.8)=2000(?-27.5)

-4474.8=2000?-55000

collect like terms

-4474.8+55000=2000?

50525=2000?

divide both sides by 2000

2000?/2000=50525/2000

initial temperature =25.26 degree Celsius

6 0

3 years ago

20 points!!!!!!Gravity would cause the rain falling in which two locations to drain an into area a. I’m assuming it’s 1 and 5 bu

zimovet [89]

Answer:

youre right i think its 1 and 5

because it cant be 2 or 3

Explanation:

I hope this answers your question(s). Have a good weekend!

7 0

2 years ago

12.Calculate the wavelength of an object moving with a velocity of 5 x105 m s-1

uranmaximum [27]

Answer:

Wavelength, $\lambda=3.3\times 10^{-18}\ m$

Explanation:

We have,

Velocity of the object, $v=5\times 10^5\ m/s$

Mass of the object, $m=4\times 10^{-22}\ kg$

It is required to find the wavelength of the object. The relation between wavelength and velocity of the object is given by :

$\lambda=\dfrac{h}{mv}$

h is Planck's constant

$\lambda=\dfrac{6.6\times 10^{-34}}{4\times 10^{-22}\times 5\times 10^5}\\\\\lambda=3.3\times 10^{-18}\ m$

So, the wavelength of the object is $3.3\times 10^{-18}\ m$ .

5 0

3 years ago

Materials that cannot carry electric energy are called

kompoz [17]

Answer:

They are called insulators

5 0

3 years ago

How manymoles of each ion are present in 175 mL of 0.147 M Fe2(SO4)3?

lilavasa [31]

Answer: 0.0257 moles of $Fe^{3+}$ and 0.0257 moles of $SO_4^{2-}$

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{moles}{\text {Volume in L}}$

moles of $Fe_2(SO_4)_3=Molarity\times {\text {Volume in L}}=0.147\times 0.175L=0.0257moles$

The balanced reaction for dissociation will be:

$Fe_2(SO_4)_3\rightarrow Fe^{3+}+SO_4^{2-}$

According to stoichiometry:

1 mole of $Fe_2(SO_4)_3$ gives 1 mole of $Fe^{3+}$ and 1 mole of $SO_4^{2-}$

Thus there will be 0.0257 moles of $Fe^{3+}$ and 0.0257 moles of $SO_4^{2-}$

8 0

3 years ago