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3 years ago

What heat travel directly to the earth

Chemistry

1 answer:

rusak2 [61]3 years ago

8 0

Radiation is the heat that travels directly to the earth

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Please help and thank you

mestny [16]

Answer:

c but not sure

Explanation:

6 0

3 years ago

Read 2 more answers

What is the density of water if you have 50.0 grams of water and a volume of 50.0 millimeters

Gnom [1K]

Answer:

$\boxed {\tt 1.0 \ g/mL}$

Explanation:

Density can be found by dividing the mass by the volume.

$d=\frac{m}{v}$

The mass of the water is 50.0 grams.

The volume of the water is 50.0 milliliters.

$m= 50.0\ g \\v=50.0 \ mL$

Substitute the values into the formula.

$d=\frac{50.0 \ g}{50.0 \ mL}$

Divide.

$d= 1.0 \ g/mL$

The density of the water is 1.0 grams per milliliter. Also, remember that the density of pure water is always 1.0 g/mL or g/cm³

8 0

3 years ago

An ionized helium atom has a mass of 6.6 × 10-27 kg and a speed of 5.3 × 105 m/s. It moves perpendicular to a 0.78-T magnetic fi

arsen [322]

Explanation:

In a magnetic field, the radius of the charged particle is as follows.

r = $\frac{mv}{qB}$

where, m = mass, v = velocity

q = charge, B = magnetic field

Therefore, q will be calculated as follows.

q = $\frac{mv}{rB}$

= $\frac{6.6 \times 10^{-27} \times 5.3 \times 10^{5}}{0.014 m \times 0.78 T}$

= $\frac{34.98 \times 10^{-22}}{0.01092}$

= $3.2 \times 10^{-19} \times \frac{1.0 e}{1.6 \times 10^{-19}C}$

= +2e

Thus, we can conclude that the charge of the ionized atom is +2e.

5 0

3 years ago

A gas has an initial volume of 455 mL at 105ºC and a final volume of 235 mL. What is its final temperature in Celsius degrees?

Oksana_A [137]

Hello!

To solve this problem we're going to use the Charles' Law. This Law describes the relationship between Volume and Temperature in an ideal gas. Applying this law we have the following equation:

$\frac{V1}{T1} = \frac{V2}{T2} \\ \\ T2= \frac{V2*T1}{V1}= \frac{235 mL * 105 ^{\circ}C }{455 mL}=54,23 ^{\circ}C$

So, the final temperature is 54,23 °C

Have a nice day!

5 0

3 years ago

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What would be the major product obtained from hydroboration–oxidation of the following alkenes?

zmey [24]

Answer:

a. 3-methylbutan-2-ol

b. 2-methylcyclohexan-1-ol

Explanation:

For this reaction, we must remember that the hydroboration is an "anti-Markovnikov" reaction. This means that the "OH" will be added at the least substituted carbon of the double bond.

In the case of 2-methyl-2-butene, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore the "OH" will be added to carbon three producing 3-methylbutan-2-ol.

For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore the "OH" will be added to carbon 2 producing 2-methylcyclohexan-1-ol.

See figure 1

I hope it helps!

8 0

3 years ago