A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
Answer:
D. Miko found an incorrect quotient and checked her work using multiplication incorrectly
Step-by-step explanation:
We are given the equation
This can be rewritten as
Miko's work is incorrect as she did not multiply by the reciprocal of denominator's fraction. Instead she just multiplied by that fractions.
The sum of the exterior angles of all polygon is always equal to 360°. The exterior angle sharing the same side with that of the right angle of the triangle is equal to 90°. If the other exterior angles are 13x and 14x then, they add up to 270°.
The equation that would allow us to determine the values of the angles are,
13x + 14x = 270
x = 10
The exterior angles are 130 and 140°. The exterior angle and the interior angle always add up to 180°.
Interior angle 1: 180° - 130° = 50°
Interior angle 2: 180° - 140° = 40°
Therefore, the measures of the two acute angles of the triangle are 50° and 40°.
Answer:
0
Step-by-step explanation:
Answer:
They are both the same triangle, with different dilations
Step-by-step explanation:
(I hope this is right, I wasn't quite sure of the context)
