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kvv77 [185]
4 years ago
10

I can't figure out the postulate or theorem that I would use. ​

Mathematics
1 answer:
Alex4 years ago
4 0

Answer:

are there any options

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What is common fraction?​
Orlov [11]
<h2><u>ANS</u></h2>

a fraction (such as ¹/₂ or ³/₄) in which the numerator and denominator are both integers and are separated by a horizontal or slanted line — compare decimal fraction.

<h3><u>T</u><u>hank</u> <u>You</u> !!!</h3>
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Alexxx [7]

Hi There!

Answer: Bowler 2

Why: if you notice that line in the box plot shows the median and it specifically shows that the meadian is 20 or so greater than Bowler 1.

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4 years ago
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What is the value of 'n' in the equation<br> -1/2(2n+4)+6=-9+4(2n+1)
sp2606 [1]

Answer:

I love algebra anyways

The ans is in the picture with the  steps how i got it

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

5 0
3 years ago
100 POINTSSS! ASAP ANSWEERR PLS
Margarita [4]

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = \frac{FV-SV}{SV}*100        (FV = final value, SV = starting value)

Percentage increase = \frac{1.4214 - 0.7107}{0.7107}*100

Percentage increase = \frac{0.7107}{0.7107}*100

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = \frac{10,201-10,100}{10,100}*100

                                                             = \frac{101}{10,100}*100

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = \frac{10,303.01-10,201}{10,201} *100

                                                              = 1%

PC of product B from 3rd to 4th year =\frac{10,406.04-10,303.01}{10,303.01}*100

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

6 0
3 years ago
What is the quotient of a number and three is negative four
Alecsey [184]

Answer:

-7

Step-by-step explanation:

7-3=4

3 0
3 years ago
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