Hi there!
![\large\boxed{(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty) }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%28-%5Cinfty%2C%20%5Csqrt%5B3%5D%7B-4%7D%29%20%5Ctext%7B%20and%20%7D%20%280%2C%20%5Cinfty%29%20%7D)
We can find the values of x for which f(x) is decreasing by finding the derivative of f(x):
Taking the derivative gets:
Find the values for which f'(x) < 0 (less than 0, so f(x) decreasing):
0 = -8/x³ - 2
2 = -8/x³
2x³ = -8
x³ = -4
![x = \sqrt[3]{-4}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B-4%7D)
Another critical point is also where the graph has an asymptote (undefined), so at x = 0.
Plug in points into the equation for f'(x) on both sides of each x value to find the intervals for which the graph is less than 0:
f'(1) = -8/1 - 2 = -10 < 0
f'(-1) = -8/(-1) - 2 = 6 > 0
f'(-2) = -8/-8 - 2 = -1 < 0
Thus, the values of x are:
![(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%20%5Csqrt%5B3%5D%7B-4%7D%29%20%5Ctext%7B%20and%20%7D%20%280%2C%20%5Cinfty%29)
Answer:
Area = 14¹/16 yd² or 14.0625 yd²
Step-by-step explanation:
2. The figure given is a square having equal sides of 3¾ yd each.
Formula for area of the square = a²
Where,
a = 3¾ yd
Plug in the value into the equation:
Area = (3¾)²
Change to improper fraction
Area = (15/4)²
Area = 225/16
Area = 14¹/16 yd² or 14.0625 yd²
Answer:
-1000
Step-by-step explanation:
1. Do the Parenthesis problem first. (PEDMAS/PEMDAS)
You should then have -10^3
2. Solve with the exponent. (-10 x 10 x 10)
You should then get your final answer, which is -1000.
Any Questions/Concerns?
N - the number
6 × n - 11 = 6n - 11
