The frequency of A4 is 440.00 Hz.
what is the frequency of A6, which is two octaves above A4?
2 answers:
To solve this problem you must apply the proccedure shown below:
1. You have the following information given in the problem above: <span>The frequency of A4 is 440.00 Hz.
2. So, you must apply the following formula to calculate the frequency of A6, which is two octaves above:
(2</span>^n)f
Where n is the octaves above and f is the known frequency.
3. Therefore, you have:
A6=(2^n)f
A6=(2^2)(440.00 Hz)
A6=1760 Hz
Therefore, the answer is: A6=1760 Hz.
The formula for getting the unknown frequecy is given by, (2∧n)×f.
Where n ⇒the number of octavos above A4 and
f ⇒the given frequency
So, the frequency of A6 is calculated as follows.
Frequency = (2∧2)×440.00
= 1760.00 Hz
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