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3 years ago

Work out m and c for the line: y−4x=−1

Mathematics

1 answer:

Eduardwww [97]3 years ago

7 0

Step-by-step explanation:

y -4x = -1

y = 4x -1

then y = Mx + b

m = 4

b = -1

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Can someone work this out ? thank you

Anna11 [10]

Answer:

Step-by-step explanation:

(x + y)² - (x - y)² = 4xy

t = a² - b²

= (√8+2)²-(√8-2)² (here, x = √8 & y = 2}

=4*√8*2

=8√8

=8√2*2*2

=8*2√2

=16√2

7 0

3 years ago

Please help<br> Solve for x.

Olegator [25]

Sum of interior angles = (n-2) × 180<span> = (5-2) x 180 = 3 x 180 = 540

so
x + 90 + 107 + 144 + 138 = 540
x + 479 = 540
x = 540 - 479
x = 61</span>

5 0

3 years ago

The number of basketball games that must be scheduled in a league with n teams is given by G(n) = (n2 - n)/2 where each team pla

Pani-rosa [81]

Answer:

There are 7 teams in the league

Step-by-step explanation:

Given that the number of games is given by:

$G(n) = \frac{(n^2-n)}{2}$

The equation will be used to determine the number of games. As we already know, that 21 games are scheduled which means G(n) is 21 so we have to find n when G(n) is 21

Putting this mathematically

$21 = \frac{n^2-n}{2}$

Multiplying equation by 2

$2*21 = 2*\frac{n^2-n}{2}\\42 = n^2-n\\n^2-n-42 = 0\\n^2-7n+6n-42 = 0\\n(n-7)+6(n-7) = 0\\(n-7)(n+6)=0\\n-7 = 0 => n=7\\n+6=0 => n=-6$

As the number of teams cannot be negative, the number of teams in league are 7.

Hence,

There are 7 teams in the league

3 0

3 years ago

How do I solve this?

Basile [38]

Answer:

the answer is 3(t+2)

Step-by-step explanation:

5 0

4 years ago

Jonny

Firlakuza [10]

Answer:

6 11/12

Step-by-step explanation:

7 - 1/12

6 11/12

3 0

3 years ago

Read 2 more answers