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seraphim [82]
3 years ago
14

What is the absolute value of -7.5?

Mathematics
2 answers:
Artemon [7]3 years ago
8 0

Answer:

3

Step-by-step explanation:

Iteru [2.4K]3 years ago
8 0

Answer:

I don't really understand the question but the absolute values of everything is

7.5

10

9

6

4

2

0

2

5

6

8

10

7.5

Step-by-step explanation:

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It takes 50 minutes to complete 2 math assignments. How long will it take to complete 5 math assignments?
Natalija [7]

Answer:

125 minutes

Step-by-step explanation:

one paper takes 25 minutes to complete. Now if we multiply that by 5 papers you get 125 minutes

7 0
2 years ago
Read 2 more answers
Find the slope of the line that passes through
Andreyy89

Answer:

-1/3

Step-by-step explanation:

Use rise over run (y2 - y1) / (x2 - x1)

Plug in the 2 points:

(y2 - y1) / (x2 - x1)

(-2 + 1) / (2 + 1)

-1/3

So, the slope is -1/3

7 0
2 years ago
Luke claims two circles are always isometric because the shape never changes. Is he correct?
olganol [36]

Luke asserts that since the shape is constant, two circles are always isometric. he is wrong. No, an isometry keeps the size and shape intact.

Given that,

Luke asserts that since the shape is constant, two circles are always isometric.

We have to say is he accurate.

The answer is

No, an isometry keeps the size and shape intact.

Because a shape-preserving transformation (movement) in the plane or in space is called an isometric transformation (or isometry). The isometric transformations include translation, rotation, and combinations thereof, such as the glide, which combines a translation with a reflection.

Therefore, Luke asserts that since the shape is constant, two circles are always isometric. he is wrong. No, an isometry keeps the size and shape intact.

To learn more about isometric visit: brainly.com/question/110297

#SPJ1

3 0
11 months ago
Need help pls someone
dimaraw [331]

\sqrt[3]{250a^{11}}=\sqrt[3]{125\cdot2a^{2+9}}=\sqrt[3]{125}\cdot\sqrt[3]{2a^2\cdot a^9}=5\sqrt[3]{2a^2}\cdot\sqrt[3]{a^9}\\\\=5\sqrt[3]{2a^2}\cdot\sqrt[3]{a^{3\cdot3}}=5\sqrt[3]{2a^2}\cdot\sqrt[3]{(a^3)^3}=5\sqrt[3]{2^2}\cdot a^3\\\\=\boxed{5a^3\sqrt[3]{2a^2}}

7 0
3 years ago
What has the diameter of a circle with the area of 484pie
andreyandreev [35.5K]
Area of a square = pie r^2.

Radius = sqrt 484 = 22.

Diameter = 2 r = 2 x 22 = 44.

Hope this helps!
7 0
3 years ago
Read 2 more answers
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