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Damm [24]
3 years ago
15

there are 3 red, 1 blue, amd 2 yellow marbles in a bag. Once a marble is selected, it is not replaced. What is the probability o

f grabbing a red and yellow marble
Mathematics
1 answer:
worty [1.4K]3 years ago
6 0

Answer: the chance you will pull a yellow it 2/6 and the chance you pull a red is 3/6

Step-by-step explanation: add all them up and you get six and then you put the number by six

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The mean weight of an adult is 69 kilograms with a variance of 121. If 31 adults are randomly selected, what is the probability
amid [387]

Answer:

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Also, important to remember that the standard deviation is the square root of the variance.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 69, \sigma = \sqrt{121} = 11, n = 31, s = \frac{11}{\sqrt{31}} = 1.97565

What is the probability that the sample mean would be greater than 70.5 kilograms?

This is 1 subtracted by the pvalue of Z when X = 70.5. So

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{70.5 - 69}{1.97565}

Z = 0.76

Z = 0.76 has a pvalue of 0.7764

1 - 0.7764 = 0.2236

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

8 0
3 years ago
5 ( 3 squared x) + 9 ( 3 squared x)
yulyashka [42]

Answer:

42x^2

Step-by-step explanation:

5(3x^{2} )+9(3x^2)\\\\=(5+9)(3x^2)\\\\=14(3x^2)\\\\=42x^2

5 0
3 years ago
Write the first four terms of a sequence given the recursive rule below: f (n) = f(n-1) -4, for all n > 2 and f(1) =32
Mars2501 [29]
I don’t know I just want points bye hdhdjjdjddjdjdjjjfjtfjgktk
7 0
2 years ago
Any one help with a step by step answer so I can write notes for future reference when working out similar questions? I need hel
max2010maxim [7]

Answer:

<em>Volume = ( About ) 2406.165 cm^3</em>

Step-by-step explanation:

If you consider a cube or a rectangular prism, you could identify it's volume through the multiplication of it's Base by height. A pyramid has 1 / 3rd that volume, so in order to take a volume of the figure to the left, we would multiply Base * height and take 1 / 3rd of that;

Square Pyramid,\\Base ( Square ) = a^2, a = length = 17.2 cm\\Height = 24.4 cm\\\\Volume = 1 / 3 ( Base ) ( Height ),\\Volume = 1 / 3 ( ( 17.2 )^2 )( 24.4 ),\\Volume = 1 / 3( 295.84 )( 24.4 ),\\\\Volume = 98.6133333333( 24.4 ),\\Volume = 2406.16533333,\\\\Volume = ( About ) 2406.165

<em>Solution ⇒ ( About ) 2406.165 cm^3</em>

<em />

Hope that helps!

3 0
3 years ago
ITEM BANK. Move to Bottom
DiKsa [7]

Answer:

Rotate 90 degrees clockwise around the origin and then translate down. Reflect across the x-axis and then reflect across the y-axis.

Step-by-step explanation:

Reflection across the y-axis. 90o counter clockwise rotation. 2. Multiple-choice. 1 minute. Q. Identify the transformation from ABC to A'B'C'. Draw the final image created by reflecting triangle RST in the x-axis and then rotating the image 90° counterclockwise about the origin. BER goo Clockwise 90c ...C-level G2-1 Reflections and Rotations ... X-axis. 00. G2-2 Rotations. 4. Rotate the figure 90° clockwise around the origin. ... Rotation 90° counter.

7 0
2 years ago
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