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3 years ago

Super easy. I just dont feel like adding it up.

Mathematics

2 answers:

garik1379 [7]3 years ago

8 0

Answer:

492

Step-by-step explanation:

9*12=108. I used January for this. there 4 weeks in it. so !08*4+15*4=492

Sedaia [141]3 years ago

5 0

Answer:

Step-by-step explanation:

lets assume that the month has 4 weeks

12h/week with 9 dollars/hour

week=12*9=108

108+15=123

123*4 weeks=492 dollars month total income

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HELP ME PLEASEE

Nina [5.8K]

Answers:

x = -8/5 or x = 8/5

Sum of the first ten terms where all terms are positive = 4092

========================================================

Explanation:

r = common ratio

first term = 4
second term = (first term)*(common ratio) = 4r
third term = (second term)*(common ratio) = (4r)*r = 4r^2

The first three terms are: 4, 4r, 4r^2

We're given that the sequence is: 4, 5x, 16

Therefore, we have these two equations

5x = 4r
4r^2 = 16

Solve the second equation for r and you should find that r = -2 or r = 2 are the only possible solutions. If r = -2, then 5x = 4r solves to x = -8/5. If r = 2, then 5x = 4r solves to x = 8/5.

-----------------

To find the sum of the first n terms, we use this geometric series formula

Sn = a*(1 - r^n)/(1 - r)

We have

a = 4 = first term
r = 2, since we want all the terms to be positive
n = 10 = number of terms to sum up

So,

Sn = a*(1 - r^n)/(1 - r)

S10 = 4*(1 - 2^10)/(1 - 2)

S10 = 4*(1 - 1024)/(-1)

S10 = 4*(-1023)/(-1)

S10 = 4092

8 0

3 years ago

Please answer CORRECTLY !!!!!! Will mark brainliest !!!!!!!!!

Gelneren [198K]

Answer:

tghghgkk

Step-by-step explanation:

8 0

3 years ago

Use the distributive property to simplify the expression 5 ( − 1 x − 6 + 6 y )

expeople1 [14]

Answer:

the answer should be -5x - 30 + 30 y

3 0

3 years ago

Read 2 more answers

Consider the following hypothesis test:

Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

$H_0: \mu\leq50\\\\H_a:\mu> 50$

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809$

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24$

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

8 0

4 years ago

23. Starting with x=0.81818181 , express x as a fraction in simplest form.

White raven [17]

You could do x=81 with the little line on the top (represents the number going on forever, and example is 0.818181818181818181818181818818181818 etc.)

6 0

3 years ago

Read 2 more answers