Answer:
$ 8,695.35
Step-by-step explanation:
This is a compound interest question
Amount after t years = A = P(1 + r/n)^nt
Where P = Initial Amount saved
r = interest rate
t = time in years
n = compounding frequency
A = 10,000
r = 3.5 %
t = 21 - 17 = 4 years
n = Compounded monthly = 12
Step 1
Converting R percent to r a decimal
r = R/100 = 3.5%/100 = 0.035 per year.
P = A / (1 + r/n)^nt
Solving our equation:
P = 10000 / ( 1 + (0.035/12)^12 ×4 =
P = $8,695.35
The principal investment required to get a total amount, principal plus interest, of $10,000.00 from interest compounded monthly at a rate of 3.5% per year for 4 years is $8,695.35.
Answer:
8
Step-by-step explanation:
360 divided by 45 is 8 calories per minute
X intercept: (- 1/7, 0)
Y intercept: (0, 1/4)
Given:
μ = 89 ng/ml, population mean
σ = 23 ng/ml, population standard deviation
Random variable, x = 100
To test P(x < 100), calculate the z-score.
z = (x-μ)/σ = (100 - 89)/23 = 0.4783
From standard tables, obtain
P(x < 100) = 0.6838 = 68.4%
Answer: 68.4%
Answer:
100 thousandths
Step-by-step explanation:
