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zepelin [54]
3 years ago
11

How do you determine the acceleration of an object?

Physics
2 answers:
Gelneren [198K]3 years ago
8 0

Are you familiar with any basic calculus? If so, we can just look at this derivative and see what's happening with our units here..

a = \frac{dv}{dt}

Here it shows that acceleration is the derivative of velocity with respect to time. In other words, we can say that:

a=\frac{\Delta v}{\Delta t}

We can read that equation as: "acceleration is the change of velocity divided by the change in time (aka the time interval)."

If you're not familiar with calculus, we can use a simple equation of motion:

v_f = v_i+at

where:

vf = final velocity

vi = initial velocity

a = acceleration

t = observed time interval

We can rearrange this equation to find:

a = \frac{v_f - v_i}{t}

This is the same exact thing we wrote before!

Shtirlitz [24]3 years ago
6 0

Answer:the correct option is A

Explanation:

To determine the acceleration of an object, you divide the change in velocity by the time interval

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What things do different atoms have in common?<br><br> Thank you!
prohojiy [21]

Answer:They come in different kinds, called elements, but each atom shares certain characteristics in common. All atoms have a dense central core called the atomic nucleus. Forming the nucleus are two kinds of particles: protons, which have a positive electrical charge, and neutrons, which have no charge

Explanation:

4 0
2 years ago
Adjacent antinodes of a standing wave on a string are 15.0 cm apart. A particle at an antinode oscillates in simple harmonic mot
timama [110]

Answer:

Explanation:

A ) Distance between two adjacent  anti-node will be equal to distance between two adjacent  nodes . So the required distance is 15 cm .

B )  wave-length, amplitude, and speed of the two traveling waves that form this pattern are as follows

wave length = same as wave length of wave pattern formed. so it is 30 cm

amplitude = 1/2 the amplitude of wave pattern formed so it is .850 / 2 = .425 cm

Speed =   frequency x wavelength ( frequency = 1 / time period )

= 1 / .075) x 30 cm

400 cm / m

C ) maximum speed

= ω A

= (2π / T) x A

= 2 X 3.14 x .85 / .075 cm / s

= 71.17 cm / s

minimum speed is zero.

D ) The shortest distance along the string between a node and an antinode

= Wavelength / 4

= 30 / 4

= 7.5 cm

3 0
3 years ago
Pushing a door closed is an example of force. true or false​
koban [17]

Answer:

True

Explanation:

I am not 100% on the answer for this question but i hope it was right

3 0
3 years ago
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What are the 3 tools used to collect weather data
sergey [27]
Anemometer, Psychrometer, <span>Barometer</span>
5 0
3 years ago
An uncharged capacitor is connected to a 21-V battery until it is fully charged, after which it is disconnected from the battery
attashe74 [19]

Answer:

The voltage bewtween the plates will be 9.5V

Explanation:

Facts:

The capacitance of a parallel plate capacitor having plate area A and plate separation d is C=ϵ0A/d.  

Where ϵ0 is the permittivity of free space.  

A capacitor filled with dielectric slab of dielectric constant K, will have a new capacitance C1=ϵ0kA/d

        C1=K(ϵ0A/d)

        C1=KC   ----------- 1

Where C is the capacitance with no dielectric and C1 is the capacitance with dielectric.

The new capacitance is k times the capacitance of the capacitor without dielectric slab.  

This implies that the charge storing capacity of a capacitor increases k times that of the capacitor without dielectric slab.

Given points

• The terminal voltage of the battery to which the capacitor is connected to charge V=25V

• A dielectric slab of paraffin of dielectric constant K=2  is inserted in the space between the capacitor plates after the fully charged capacitor is disconnected

The charge stored in the original capacitor Q=CV

The charge stored in the original capacitor after inserting dielectric Q1=C1V1

The law of conservation of energy states that the energy stored is constant:

i.e Charge stored in the original capacitor is same as charge stored after the dielectric is inserted.

Q   =  Q1

CV = C1V1

  CV = C1V1  -------2

We derived C1=KC from equation 1. Inserting this into equation 2

   CV = KCV1

 V1 = (CV)/KC

         V/K

       = 21/2.2

      = 9.5

4 0
3 years ago
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