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Sergeu [11.5K]
4 years ago
7

What is the electrical force between q1 and q2? Recall that k = 8.99 × 109 N•meters squared over Coulombs squared.. 4.3 × 10 N 3

.5 × 10 N –5.4 × 10 N –5.8 × 10 N?
Physics
2 answers:
Rudiy274 years ago
7 0

Answer:

Explanation:

Incomplete question but for understanding.

We want to find the electrical force between two charges, then you can use the coulombs law which states that the force of attraction or repulsion between two charges is directly proportional to the product of the two charges and inversely proportional to the square of their distance apart,

So,

F = kq1•q2 / r²

Where k is a constant and it is given as

K = 8.99 × 10^9 Nm²/C²

q1 and q2 are the charges and in this question it is not given, so the question is incomplete. Let assume that,

q1 = - 1.609 × 10^-19 C electron

q2 = 1.609 × 10^-19 C proton

Since unlike charges attract, then it is force of attraction

Also, r is the distance apart and it is not given, let assume the distance between the two charges is 2 × 10^-5m

Then,

F = kq1•q2 / r²

F = 8.99 × 10^9 × 1.609 × 10^-19 × 1.609 × 10^-19 / (2 × 10^-5)²

F = 5.82 × 10^-19 N

Andru [333]4 years ago
6 0

Answer:

c –5.4 × 1010 N on edge

Explanation:

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Answer: (a)

Explanation:

Given

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For elastic collision, the velocity of the center of mass remains the same as the momentum is conserved and there is no acceleration involved.

So, for elastic collision velocity V_f_2=\frac{4}{5}V

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4 years ago
One end of an elastic cord is fastened to a steel beam. A metal weight with a mass of 68 kg is attached to the other end of the
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Hi there!

We can use IMPULSE to solve.

Recall impulse:

I = \Delta p = m\Delta v = m(v_f - v_i)

Begin by calculating the impulse. Assuming up to be the + direction, and down to be the - direction.

I = 68(11 - (-14)) = 68 \cdot 25 = 1700 kg\frac{m}{s}

Now, we can calculate force using this value:

I = F \cdot t\\\\F = \frac{I}{t}\\\\F = \frac{1700}{0.85} = \boxed{2000 N}

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4 0
3 years ago
When you ride a bicycle at constant speed, nearly all the energy you expend goes into the work you do against the drag force of
ratelena [41]

Answer:

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kakasveta [241]

Answer:

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Explanation:

mark me brainliest!!

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