Answer:
Area of play ground = Length × Breadth = 750 × 250 = 187500. a Cost of levelling the ground = 187500 × 16 100 = Rs . 30000
Answer:
x = 0.2(10^y/a).
Step-by-step explanation:
y = alog(5x)
y = log(5x)^a) By the definition of a log:
(5x)^a = 10^y
5x = (10^y) ^ 1/a
x = 0.2(10^y/a)
Answer:
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
Step-by-step explanation:
Here n= 20
Sample mean GPA = x`= 2.84
Standard mean GPA = u= 2.55
Standard deviation = s= 0.45.
Level of Significance.= ∝ = 0.01
The hypothesis are formulated as
H0: u1=u2 i.e the GPA of night students is same as the mean GPA of day students
against the claim
Ha: u1≠u2
i.e the GPA of night students is different from the mea GPA of day students
For two tailed test the critical value is z ≥ z∝/2= ± 2.58
The test statistic
Z= x`-u/s/√n
z= 2.84-2.55/0.45/√20
z= 0.1441
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
It would be 340%. First, you need to find out what the fraction is for 2/5. 2/5 as a decimal would be .4. Next you put that back with the three which is 3.4. After that, you need to turn that into a percentage by multiplying it by 100 which then equals 340. add the % to it and that gives you 340%.
90% of 10 is 9 have a great day
