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3 years ago

The graph shows the cost of ice cream. If a teacher wants to buy 20 cones, how much will it cost ?

Mathematics

1 answer:

Volgvan3 years ago

6 0

Answer:

you cannot see the graph. So I cannot answer this question

Step-by-step explanation:

if you add the graph maybe I can help :D

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The perimeter of a child’s rectangular sandbox is 18 feet . if the length of the sandbox is one foot longer than the width , wha

Andrew [12]

Answer:

2(b+1+b)= 18

Step-by-step explanation:

Perimeter of a rectangle= 2(l+b)

18 feet= 2(l+b)

length: l, breadth: b

Because the length of the sandbox is 1 foot longer, it will be:

b+1 = l

Substitute l with b+1

2(b+1+b)= 18

8 0

2 years ago

What is the reciprocal of 2 3/8

Maksim231197 [3]

Basically 0.42105263157

8 0

2 years ago

Read 2 more answers

In 2011, a train carried 8% more passengers than in 2010. In 2012 , it carried 8% more passengers than in 2011. Find the percent

hjlf

Answer:

there was a 16% increase since 2010 to 2012

Step-by-step explanation:

lets say the train had 100 people on it in 2010 and in 2011 it had an 8% increase which then brings you to 8 plus 100 and you get 108.

Now in 2012 there was an increase 8%, so you will add 8 to your previous answer 108 and receive 116. So now there was 16 more passengers in 2012 than in 2010. Transfer the 16 passengers into 16% and you now have your answer.

3 0

2 years ago

Which of the following is not a congruence transformation? A) a reflection over the axis b) a dilation with scale factor 0.5 c)

Wewaii [24]

It would be c because this isn't transforming it

6 0

3 years ago

PLEASE HELP QUICK!! WILL OFFER 100 POINTS TO THE FIRST ONE THAT ANSWERS

Reil [10]

Given

$x+1 = \sqrt{7x+15}$

We have to set the restraint

$x+1\geq 0 \iff x \geq -1$

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

$(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0$

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

$x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}$

So, we have to impose

$x-7\geq 0 \iff x \geq 7$

Squaring both sides, we have

$(x-7)^2=x-1 \iff x^2-14x+49=x-1 \iff x^2-15x+50 = 0$

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.

7 0

3 years ago