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SIZIF [17.4K]
3 years ago
11

An apple weighs at 1N. the net force on the apple when it is in free fall is?

Physics
1 answer:
ololo11 [35]3 years ago
3 0
The weight of an object <em>IS</em> the net force on it when it's in free-fall.

("Free fall" means that the only force acting on it is the force of gravity.
The force of gravity on an object is the force we call its "weight".)
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3 0
3 years ago
An Olympic track runner starts from rest and has an acceleration of 2.4 m/s2 for 3.6 s, then has zero acceleration for the remai
rjkz [21]

Answer:

The runner's speed at the following times would remain 8.64 m/s.

Explanation:

Acceleration definition: Acceleration is rate of change in velocity of an object with respect to time.

In this case, after 3.6 seconds the acceleration is zero, it means that the velocity of the runner after 3.6 seconds is not changing and it will remain constant for the remainder of the race. Now, we have to find the velocity of the runner that he had after 3.6 seconds and that would be the runner's speed for the remainder of the race. For this we use first equation of motion.

First equation of motion:        Vf = Vi + a×t

Vf stands for final velocity

Vi stands for initial velocity

a stands for acceleration

t stands for time

In the question, it is mentioned that the runner starts from rest so its initial velocity (Vi) will be 0 m/s.

The acceleration (a) is given as 2.4 m/s²

The time (t) is given as 3.6 s

Now put the values of Vi, a and t in first equation of motion

                       Vf = Vi + a×t

                       Vf = 0 + 2.4×3.6

                       Vf = 2.4×3.6

                       Vf = 8.64 m/s

So,the runner's speed at the following times would remain 8.64 m/s.

5 0
3 years ago
Which is the answer for this question
Brut [27]

Explanation:

Light is not invisible

sound cant travel in a vacuum

3 0
2 years ago
Read 2 more answers
Q. A mass of 300g is lifted to a<br> height of 10m<br> 205 by a person. Calculate his work done
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A=mgh
m=300g=0.3kg
g=9,81 m/s^2
h=10m
A=29.43J
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2 years ago
I need someone that has a course hero subscription to help me I need all the pages
SVETLANKA909090 [29]

Answer:

So what's the answer???

Explanation:

8 0
3 years ago
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