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3 years ago

Q1. What is the frequency of rotation of 1000 loop coil of area 20cm2 in a magnetic field of 5T to

Physics

1 answer:

Eduardwww [97]3 years ago

4 0

Answer:

Explanation:

Emf e generated in a coil with no of turn n and area A rotating in a magnetic field B with angular speed of ω is given by the expression

e = e₀ sinωt

where e₀ = nωAB which is the maximum emf generated

Putting the given values

15.7 = 1000xω x 20 x 10⁻² x 5

ω = .0157

frequency of rotation

= ω / 2π

= .0157 / 2 x 3.14

= .0025 /s

9 rotation / hour .

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What are the charged particles called in thermoshpere?

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They are called Ions
Definition is this: atom of molecule with a net electric charge caused by the loss or gain of one or more electrons.
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3 years ago

Which would cause the greatest increase in the acceleration of a satellite?

vagabundo [1.1K]

Its C. a decrease in the radius and an increase in the tangential speed ,I'm 100% sure

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4 years ago

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A bullet B of mass mB traveling with a speed v0 = 1400 m/s ricochets off a fixed steel plate A of mass mA. Let mA ≫ mB so that i

Greeley [361]

Answer:

Rebounce angle is 345°

Rebounce speed is 989.95m/s

Explanation:

Calculate the x component of the velocity of the bullet before impact by using the following relation:

Vbx= Vb Cos thetha

Here, is the initial velocity of the bullet, Vo = 1400m/s and is the incidence angle of the bullet.= theta = 15°

Substituting

Vbx = Cos15 ×1400 = 1352.30m/s

Calculate the y component using the relation:

Vby = Vo Sin theta

Vby = sin 15° × 1400

Vby = 362.35m/s

The rebounce angle = 360 - incidence angle

Rebounce angle =( 360 - 15)° = 345°

The rebound speed V' = Vby - Vbx

V' = (1352.30 - 362.35)m/s

V' = 989.95 m/s

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4 years ago

A particular cylindrical bucket has a height of 36.0 cm, and the radius of its circular cross-section is 15 cm. The bucket is em

Andrew [12]

Answer:

12 cm

Explanation:

$P_1$ = Initial pressure = $P_a=1\times 10^5\ Pa$

$P_2$ = Final pressure = $P_a+\rho_w gh$

h = Depth of cylinder = 36 cm

g = Acceleration due to gravity = 10 m/s²

$\rho_w$ = Density of water = 1000 kg/m³

$h_1$ = Depth of lake = 20 m

From the ideal gas relation we have

$P_1V_1=P_2V_2\\\Rightarrow P_a(\pi r^2h)=(P_a+\rho_w gh_1)\pi r^2h'\\\Rightarrow 1\times 10^5\times 36=(1\times 10^5+1000\times 10\times 20)h'\\\Rightarrow h'=\dfrac{1\times 10^5\times 36}{1\times 10^5+1000\times 10\times 20}\\\Rightarrow h'=12\ cm$

The height of the cylinder of air in the bucket when the bucket is at the given depth is 12 cm

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3 years ago

To understand the forces between a bar magnet and 1. a stationary charge, 2. a moving charge, and 3. a ferromagnetic object. A b

Brums [2.3K]

Answer:

Explanation:

1. If the charge is stationary and it is not moving, then the magnetic force will be zero, since the velocity is 0m/s

From the formula of magnetic force

F = q(V×B)

And since V is 0, then, the magnetic force is zero

F = 0N,

No torque at all.

2. The moving charge interacts with the fixed magnet. The force between them is at a maximum when the velocity of the charge is perpendicular to the magnetic field.

From the formula of magnetic force

F = q( V×B)

V × B = |V|•|B| Sinθ

So, Sinθ has its highest value at 90° in the range of 0-360°

So, the force will have a maximum value when the moving charge is perpendicular to the magnetic field

Now, since the magnetic field is in the positive y-direction, for the force to be maximum the electron must move the positive x-direction.

So the force will be in the positive z-direction(since i×j= k).

3. Now, the charge is replaced by an electrically neutral piece of initially unmagnetized soft iron (e.g. nail) that is not moving. This result into the magnetic experience a force due to the iron fillings attracting its north pole.

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3 years ago