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2 years ago

Molly also buys a bag of 8 apples for $3.60. Write and

Mathematics

1 answer:

Vlada [557]2 years ago

4 0

Answer:

each apple is 0.45

Step-by-step explanation:

$3.60 divided by 8 is equal to 0.45.

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Ryan runs 9 miles in 73 minutes. How many minutes does he take per mile?

Bad White [126]

I think, it would take 8.11 minutes to do one mile...

3 0

2 years ago

Olivia takes twelve laps on a long track in fifteen minutes. how much time will it take her to skate thirty laps ?

Firdavs [7]

Answer:

C. 37.5 minutes

Step-by-step explanation:

You can set up a proportion to help you figure this out.

12/15=30/x (in this proportion, the number of laps are both on the numerator and the time it takes her is on the denomiator.)

Now, just cross multiply and your equations should be: 12·x=15·30, which equals to 12x=450.

Divide 12 on both sides and x=37.5

3 0

2 years ago

Read 2 more answers

If A and B are independent events with P(A) = 0.5 and P(B) = 0.5, then P(A ∩ B) a. is 1.00. b. is 0.5. c. is 0.00. d. None of th

erastova [34]

Answer:

The answer is (d) "None of the these alternatives are correct"

Step-by-step explanation:

If two events A and B are independent, the probability of the intersection $P(A\cap B)$ is defined as:

$P(A\cap B)=P(A)\cdot P(B)$

Therefore, in the exercise:

$P(A\cap B)=P(A)\cdot P(B)=0.5\cdot 0.5\\P(A\cap B)=0.25$

which give (d) "None of the these alternatives are correct"

3 0

2 years ago

What mistake did Fumio make? He did not distribute the 2 to both components of vector u. He added vectors v and w before distrib

chubhunter [2.5K]

Answer: A

Step-by-step explanation:

4 0

2 years ago

(x5 + y5) ÷ (x + y) please answer ASAP

Shkiper50 [21]

Answer:

$\frac{x^5+y^5}{x+y}=x^4-x^3y+x^2y^2-xy^3+y^4$

Step-by-step explanation:

Given the expression

$\left(x^5+y^5\right)\div \left(x+y\right)$

$\mathrm{Apply\:factoring\:rule:\:}x^n+y^n=\left(x+y\right)\left(x^{n-1}-x^{n-2}y+\:\dots \:-\:xy^{n-2}\:+\:y^{n-1}\right)\:\quad \quad \mathrm{n\:is\:odd}$

$x^5+y^5=\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)$

$=\frac{\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)}{x+y}$

Cancel the common factor: x+y

$=x^4-x^3y+x^2y^2-xy^3+y^4$

Thus,

$\frac{x^5+y^5}{x+y}=x^4-x^3y+x^2y^2-xy^3+y^4$

3 0

2 years ago