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elena-s [515]
3 years ago
10

U Pause o Help Jackson has a sprinkler that rotates in a circle with a 6 foot radius. What is the approximate area that Jackson

can expect the sprinkler to cover?​
Mathematics
1 answer:
lidiya [134]3 years ago
7 0
12 x pie (I can’t fine the symbol for it tho)
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The length of a rectangle is represented by the function L(x) = 5x. The width of that same rectangle is represented by the funct
Mazyrski [523]

Remember that the area of a rectangle is the length of the rectangle multiplied by the width of the rectangle.


In this case, we could say (where A(x) is the area of the rectangle):

A(x) = L(x) \cdot W(x)


Substituting the values the problem gave us for L(x) and W(x), we can find the formula for A in terms of x, which is:

A(x) = (5x) \cdot (2x^2 - 4x + 13) = (10x^3 - 20x^2 + 65x)


The formula for the area of the rectangle would be A(x) = 10x³ - 20x² + 65x.

3 0
3 years ago
Read 2 more answers
The weight of male Americans between the ages of 18 and 25 is normally distributed, with a mean of 160.4 lb and a standard devia
torisob [31]

you need to substitute.... then do: 160.4(mean)+2(x)*27(z)= 214.4lb

6 0
3 years ago
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Please help<br> Please also explain
schepotkina [342]

Answer: it is equal

Step-by-step explanation: you subtract 15-4 which equals 11. the exponent is the only thing being subtracted since it's a fraction. therefore it equals 10(11)

3 0
3 years ago
The number of people in a car that crosses a certain bridge is represented by the random variable X, which has a mean value μX =
Alona [7]

Let Y be the total amount of money paid by any given set of passengers. If there are X passengers in a car, then the driver must pay a toll of Y=0.5X+3.

Then Y has first moment (equal to the mean)

E[Y]=E[0.5X+3]=0.5E[X]+3E[1]=0.5\mu_X+3=\boxed{4.35}

and second moment

E[Y^2]=E[0.25X^2+3X+9]=0.25E[X^2]+3E[X]+9E[1]=0.25E[X^2]+3\mu_X+9

Recall that the variance is the difference between the first two moments:

\mathrm{Var}[X]=E[X^2]-E[X]^2\implies E[X^2]={\sigma^2}_X+{\mu_X}^2

\implies E[Y^2]=0.25({\sigma^2}_X+{\mu_X}^2)+3\mu_X+9\approx19.22

\implies\mathrm{Var}[Y]=E[Y^2]-E[Y]^2=\boxed{0.3}

3 0
4 years ago
Four watermelons cost $22. Complete the table.
Elodia [21]

Answer:

which table xD

Step-by-step explanation:

:ooo

6 0
3 years ago
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