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3 years ago

10

U Pause o Help Jackson has a sprinkler that rotates in a circle with a 6 foot radius. What is the approximate area that Jackson

can expect the sprinkler to cover?

1 answer:

lidiya [134]3 years ago

7 0

12 x pie (I can’t fine the symbol for it tho)

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36 members of the art

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3 years ago

Evaluate 2a + 4b<br> if a = 10 and b = 6

iris [78.8K]

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44

Step-by-step explanation:

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Suppose that you roll a pair of honest dice. If you roll a total of 6, you win $18; if you roll a total of 11, you win $72;

ser-zykov [4K]

You can roll a total of 6 by rolling (1, 5), (2, 4), (3, 3), (4, 2), or (5, 1). There are 36 total possible rolls that can be obtained, so you roll a total of 6 with probability 5/36.

You can roll a total of 11 by rolling (5, 6) or (6, 5), hence with probability 2/36 = 1/18.

Any of the other remaining 29 outcomes occurs with probability 29/36.

The expected value of your winnings is

$18*5/36 + $72*1/18 - $9*29/36 = -$0.75

so the answer is E.

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3 years ago

How do i solve 3x² - 8x + 2 = 0 using quadratic formula?

DENIUS [597]

$3x^2 - 8x + 2 = 0\\ \\a=3 , \ \ b=-8 , \ \ c=2 \\ \\x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a} =\frac{8-\sqrt{ (-8)^2-4 \cdot 3\cdot 2}}{2 \cdot 3} =\frac{8-\sqrt{ 64-24 }}{6} =\\ \\ =\frac{8-\sqrt{40 }}{6} = \frac{ 8-\sqrt{4\cdot 10 } }{6} = \frac{ 8-2\sqrt{ 10 }}{6} = \frac{2 (4-\sqrt{ 10 })}{6} = \frac{ 4-\sqrt{ 10 } }{3}$

$x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a} =\frac{8+\sqrt{ (-8)^2-4 \cdot 3\cdot 2}}{2 \cdot 3} = \frac{ 4+\sqrt{ 10 } }{3}$

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Inessa05 [86]

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Step-by-step explanation:

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