Volume of reg sq. pyramid = vp
vp = 1/3×s^2×h, where s = side and h = height
Volume of cone = vc =1/3×h×pi×r^2
Now we know that h is the same for both, and the cones diameter = s of square base, so radius (r) = 1/2 s
so now vc = 1/3×h×pi×(1/2s)^2
let's remove the same items for both vc and vp
so 1/3 and h
now let's plug an arbitrary number into each:
vc = pi (10/2)^2 = 3.14×25 = 78.54
vp = s^2 = 10^2 = 100
So any square pyramid has slightly more volume than the cone
Y=2X
Looking at the line you can see that it is moving up from left to right, making it positive. So -2X and -12X are incorrect.
Next we can find the slope by putting rise over run. Chose a point on the line, I’ll use (2,4).
On this point we rise to 4 and run over to 2.
So for rise over run we have 4/2 which is 2.
So y=2x is correct.
10% of 27,650 is 2,765
5% of 27,650 is half of 2,765 = 1,382.50.
answer= 5%.
Use this formula:
a) d=11
Work:
d=sqrt((4-(-7))^2+(5-5)^2
d=sqrt((11)^2+(0)^2)
d=sqrt(121+0)
d=sqrt(121)
d=11
b) d=4
c) d = 16
d) d=160
e) d=12
Trendline is drawn over the data points of the scatter plot in order to project which way the plot is directed. If we want to draw the trend line, we should consider the points that will best represent the data. Therefore, the answer to this item is letter C.
