Rearrange equation.h=-16t^2-6t+110 h = 0 at the ground. divide both sides of the equation by (-2) to yield: 0 = 8t^2+3t - 55 and use quadratic equation h=<span>-b±√(b2 - 4ac)</span> 2awhere a = 8, b= 3, c=-55 Substitute: [-3 ± √(9 - 4*8*(-55))] / (16) = [6 ± √(36 + 1760)] / (16) = [6 ± √(1796)] /16 = (6 ± 42.3792)/16. Time can only be positive for this problem...so discard negative answer. = 48.3792/16 = 3.02 seconds
The equation that models the students is a linear equation
The equation that models the number of students in each bus is 6x = 216, and the number of students in each bus is 36
<h3>How to determine the equation?</h3>
The given parameters are:
Students = 221
Van = 5
The rest students = 6 buses
Start by calculating the number of students remaining:
Remaining students = 221 - 5
Remaining students = 216
Represent the number of students in each bus with x.
So, we have:
6 buses * x = Remaining students
This gives
6x = 216
Divide both sides by 6
x = 36
Hence, the equation that models the number of students in each bus is 6x = 216, and the number of students in each bus is 36
Read more about linear equations at:
brainly.com/question/15602982
Answer:
x=36
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange x - 2y = - 3 into this form
Subtract x from both sides
- 2y = - x - 3 ( divide all terms by - 2 )
y = 
x + 
← in slope- intercept form
with m =
• Parallel lines have equal slopes, thus
y = x + c ← is the partial equation
To find c substitute (- 1, 2) into the partial equation
2 = - + c ⇒ c = 2 + = 
y = x + ← in slope- intercept form
Multiply through by 2
2y = x + 5 ( subtract 2y from both sides )
0 = x - 2y + 5 ( subtract 5 from both sides )
- 5 = x - 2y, thus
x - 2y = - 5 ← in standard form
