Answer:
The volume of the liquid remaining in the beaker is 0.24615 l
Explanation:
The initial volume of liquid in the beaker = 0.250 l
The volume of liquid the student pours out of the beaker = 0.00385 l
The volume of liquid remaining in the beaker, V, is given as follows;
V = The initial volume of liquid in the beaker - The volume of liquid the student pours out of the beaker
Therefore, we have;
V = 0.250 l - 0.00385 l = 0.24615 l
The volume of the liquid remaining in the beaker is 0.24615 l.
The standard ambient temperature and pressure are
Temperature =298 K
Pressure = 1atm
The density of gas is 1.5328 g/L
density = mass of gas per unit volume
the ideal gas equation is
PV = nRT
P = pressure = 1 atm
V = volume
n = moles
R= gas constant = 0.0821 Latm/mol K
T = 298 K
moles = mass / molar mass
so we can write
n/V = density / molar mass
Putting values
Thus molar mass of gas is 37.50g/mol
I believe the answer is "electron"