Answer:
9.9652g of water
Explanation:
The establishment of the liquid-vapor equilibrium occurs when the vapour of water is equal to vapour pressurem 26.7 mmHg. Using gas law it is possible to know how many moles exert that pressure, thus:
n = PV / RT
Where P is pressure 26,7 mmHg (0.0351atm), V is volume (1.350L), R is gas constant (0.082 atmL/molK) and T is temperature (27°C + 273,15 = 300.15K)
Replacing:
n = 0.0351atm×1.350L / 0.082atmL/molK×300.15K
n = 1.93x10⁻³ moles of water are in gaseous phase. In grams:
1.93x10⁻³ moles × (18.01g / 1mol) = <u><em>0.0348g of water</em></u>
<u><em /></u>
As the initial mass of water was 10g, the mass of water that remains in liquid phase is:
10g - 0.0348g = <em>9.9652g of water</em>
<em />
I hope it helps!
Answer:
Here's what I get
Explanation:
The Lewis structure of SO₃ consists of a central sulfur atom double-bonded to each of three oxygen atoms that points to the corners of an equilateral triangle.
A ball-and-stick model of SO₃ is shown below.
Answer:
114mL.
Explanation: hope this helped
they are made by of two types of elementary particles
electrons and quarks
quetion answered by
(jacemorris04)
