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maks197457 [2]
3 years ago
8

What is conserved during all chemical reactions?

Chemistry
1 answer:
Stels [109]3 years ago
8 0

Answer:

In a chemical reaction the total mass of all the substances taking part in the reaction remains the same. ... The law of conservation of mass states that the total mass of substances taking part in a chemical reaction is conserved during the reaction.

Explanation:

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4. How many atoms are contained in 3.55 moles of sodium chloride?
DochEvi [55]

Hey there!

There are 6.022 x 10²³ particles in 1 mole.

We have 3.55 moles.

6.022 x 10²³ x 3.55

2.14 x 10²⁴

This is how many particles we have.

NaCl has 2 atoms for every unit.

So we multiply this by 2.

2 x 2.14 x 10²⁴ = 4.28 x 10²⁴

There are 4.28 x 10²⁴ atoms in 3.55 moles of sodium chloride.

Hope this helps!

5 0
3 years ago
Read 2 more answers
3. Theoretically how many grams of magnesium is required to produce to 5.0 g of
FinnZ [79.3K]

Answer:

3grams

Explanation:

The reaction for the production of Magnesium dioxide will be

Mg + O2  → MgO

we have 5g of MgO (molar mass 40g)

no of moles of MgO = 5/40 = 0.125

Using unitary method we have

1 mole of Mg require 1 mole of MgO

0.125 Mole of MgO = 0.125mole of Mg

n = given mass /molar mass

0.125 = mass / molar mass

mass = 0.125* 24 = 3grams

8 0
3 years ago
If 110g of copper sulphate is present in 550g of solution calculate the concentration of solution
Bingel [31]

Answer:

20%

Explanation:

mass by mass percentage of a solution =(mass of solute)/(mass of solution)

mass of solute=550g

therefore 110×100/550=20%

hope u will understand .:") credit to the owner

7 0
4 years ago
A galvanic cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that contains Cu(s) and Cu2+(aq). W
Agata [3.3K]

Answer : The 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Explanation :

Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the voltaic cell or electrochemical cell.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

We are taking the value of standard reduction potential form the standard table.

E^0_{[Ag^{+}/Ag]}=+0.80V

E^0_{[Cu^{2+}/Cu]}=+0.34V

In this cell, the component that has lower standard reduction potential gets oxidized and that is added to the anode electrode. The second forms the cathode electrode.

The balanced two-half reactions will be,

Oxidation half reaction (Anode) : Cu(s)\rightarrow Cu^{2+}(aq)+2e^-

Reduction half reaction (Cathode) : Ag^{+}(aq)+e^-\rightarrow Ag(s)

Thus the overall reaction will be,

Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

From this we conclude that, 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Hence, the 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

7 0
3 years ago
A compound contains 1.10 mol of K, 0.55 mol of Te, and 1.65 mol of O. What is the simplest formula of this compound?
sergiy2304 [10]

Answer:

K_2TeO_3

Explanation:

Given that:-

Moles of K = 1.10 moles

Moles of Te = 0.55 moles

Moles of O = 1.65 moles

Taking the simplest ratio of the moles of the elements as:-

   K : Te : O

1.10 : 0.55 : 1.65  

   2 :     1   : 3

Empirical formulas is the simplest or reduced ratio of the elements in the compound. So, the empirical formula is:- K_2TeO_3

6 0
3 years ago
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