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miv72 [106K]
3 years ago
6

All the following are steps included in linking amino acids to form chains except

Chemistry
1 answer:
ss7ja [257]3 years ago
4 0
The correct option is D.
During peptide formation, when two amino acids come together, a hydrogen atom and two molecules of oxygen are released in form of water molecules. The amino acid that present the carboxyl group to the reaction loses an hydroxyl group while the amino acid that present the amino group to the reaction loses a hydrogen.
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Given, 2Ca + O2 -> 2CaO, what is the 2 located in front of calcium called??
EleoNora [17]
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shusha [124]

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Explanation:

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8 0
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astraxan [27]
Let's eliminate the options one at a time.
A) They indeed all can donate an extra proton (or H+) so they are acidic. A is true.
B) They will not taste bitter, as acids, like those listed, will be sour. B is false
C) A pH above 7 means that something is basic, not acidic. C is false
D) Litmus paper turns blue when exposed to something basic, and red when exposed to something acidic. D is false.

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4 0
4 years ago
What is the heat capacity of crystalline calcium carbide at 49.0°C?
Olenka [21]

Explanation:

Formula to calculate heat capacity is as follows.

               C_{p} = a + bT + cT^{-2}

where, a, b and c are constants.

Their values at 49.0^{o}C are as follows.

     a = 68.62 \times 10^{-3}        

     b = 1.19 \times 10^{-5}

     c = -8.66 \times 10^{10} \times 10^{-8}

Hence, putting the given values into the above formula as follows.

               C_{p} = a + bT + cT^{-2}

    = 68.62 \times 10^{-3} + 1.19 \times 10^{-5} \times 49.0 + -8.66 \times 10^{10} \times 10^{-8} \times (49.0)^{-2} kJ/mol K    

                             = 14.43 kJ/mol K

Thus, we can conclude that the heat capacity of crystalline calcium carbide at 49.0^{o}C is 14.43 kJ/mol K.

4 0
3 years ago
A chemist makes a solution of Ca(NO3)2 by dissolving 21.3 g Ca(NO3)2 in water to make 100.0 mL of solution. What is the concentr
anastassius [24]

Answer:

[NO₃⁻ ] = 2.596 M

Explanation:

Ca(NO₃)₂ dissolves in water according to the following equation:

Ca(NO₃)₂ ⇒ Ca²⁺ + 2NO₃⁻

The moles of Ca(NO₃)₂ that dissolve is found as followed:

(21.3 g) / (164.10 g/mol) = 0.1298... mol

The number of NO₃⁻ ions are related to the above quantity by the molar ratio:

(0.1298 mol Ca(NO₃)₂) (2NO₃⁻/Ca(NO₃)₂) = 0.2596...mol NO₃⁻

The concentration of the nitrate ions is then calculated:

[NO₃⁻ ] = (0.2596...mol) / (100.0ml) x (1000mL/L) = 2.596 M

6 0
3 years ago
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