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Veronika [31]
2 years ago
5

A liquid has a density of 0.87g/ml. What volume is occupied by 25g of liquid

Chemistry
1 answer:
irga5000 [103]2 years ago
5 0

Answer:

29 mL

Explanation:

<h3>Equation</h3>

The question needs us to find the volume of the liquid. The equation for volume using density and mass is:

Volume = Mass / Density

<h3>Solve</h3>

We can substitute the given values for density and mass into the equation:

V=\frac{25\ g}{0.87\ g/ml}

V\approx29\ mL

<h3>Additional Comments</h3>

The answer we obtained (29 mL) is rounded to two significant figures. When multiplying or dividing, the amount of significant figures in the final answer is always the least amount of significant figures in one of the values.

Below are the significant figure rules:

Nonzero digits will always be significant (eg. 54 --> 2 significant figures)

Zeroes at the beginning of a number will never be significant (eg. 0.1 --> 1 significant figure)

Zeroes between two nonzero digits will always be significant (eg. 504 --> 3 significant figures)

Zeroes following a number will always be significant if the number contains a decimal point (eg. 40.0 --> 3 significant figures)

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A gas occupies a volume of 67.54 liters at 158°C and 4.87 atm pressure. Calculate the number of moles of this gas.
Katarina [22]

Answer:

The number of moles of the gas is 9.295 moles or 9.30 moles

Explanation:

We use PV = nRT

Where P = 4.87 atm;

V = 67.54 L

R= 0.0821Latm/molK

T = 158 C = 158 +273 K = 431 K

the number of moles can be obtained by substituting the values in the respective columns and solve for n

n = PV / RT

n = 4.87 * 67.54 / 0.0821 * 431

n = 328.9198 / 35.3851

n = 9.295moles

The number of moles is approximately 9.30moles.

6 0
3 years ago
Help please! I'd appreciate it 
babymother [125]

Answer:

16.56 g

Explanation:

Mass is the production of Volume and Density.

m = V. d = 6 × 2.76 = 16.56 g

6 0
3 years ago
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Elena L [17]

#1. The condition of the atmosphere at a certain time and certain place

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7 0
3 years ago
According to the Law of Conservation of Mass, how much water is produced if 22.5 g of
nadezda [96]

Answer: The amount of water produced is 9.3 grams

Explanation:

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CH_4+2O_2\rightarrow CO_2+2H_2O

mass of reactants = mass of methane + mass of oxygen = 22.5 g + 35.7 g = 58.2 g

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48.9 g +  mass of water = 58.2 g

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3 years ago
After fertilization, female cones become very:<br> sticky<br> light<br> O hard
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Answer:

light

Explanation:

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