The volume of a 14.00g of nitrogen at 5.64atm and 315K is 4.59L.
<h3>How to calculate volume?</h3>
The volume of an ideal gas can be calculated using the following ideal gas equation formula;
PV = nRT
Where;
- P = pressure (atm)
- V = volume (L)
- n = number of moles
- R = gas law constant
- T = temperature
An ideal gas is a hypothetical gas, whose molecules exhibit no interaction, and undergo elastic collision with each other and with the walls of the container.
The number of moles in 14g of nitrogen can be calculated as follows:
moles = 14g ÷ 14g/mol = 1mol
5.64 × V = 1 × 0.0821 × 315
5.64V = 25.86
V = 25.86 ÷ 5.64
V = 4.59L
Therefore, 4.59L is the volume of the gas
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Answer:
volume = 2128L
Explanation:
volume at stp = 22.4dm³ =22400L
CO2 = 12 + 2(16) = 44
4.20/44 = volume/22400L
0.095 = volume/22400L
volume = 0.095 x 22400
volume = 2128L
Answer:
Kp = 0.0146
Explanation:
We can solve this equilibrium problem using an ICE Table. There are 3 stages: I(Initial), C(Change) and E(Equilibrium). Only <em>gases</em> and <em>aqueous species</em> participate in the equilibrium.
NH₄CO₂NH₂ ⇄ 2 NH₃(g) + CO₂(g)
I 0 0
C +2x +x
E 2x x
<em>Total gas pressure is equal to the sum of partial pressures at equilibrium.</em>
pNH₃ + pCO₂ = 0.463 atm
2x + x = 0.463 atm
3 x = 0.463 atm
x = 0.154 atm
Then,
pNH₃ = 0.308 atm
pCO₂ = 0.154 atm
We can replace this data in the Kp expression.
