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2 years ago

5

Gina wants to take dance classes. She compares two dance studios to determine which has the best deal for her. Dance World charg

es a rate for each class. Toe Tappers charges a rate for each class plus a one-time registration fee. The system of equations shown models the total costs for taking x classes at each.
Dance World: y = 15x
Toe Tappers: y = 25 + 12.5x

How many classes would Gina need to take for the total cost to be the same at both dance studios?

10
15
100
150

1 answer:

jonny [76]2 years ago

4 0

Answer:

The correct answer is A: 10

Step-by-step explanation:

Same Question : brainly.com/question/17110602

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PLZ HELP! ASAP!!! I WILL GIVE BRAINLIEST

Ira Lisetskai [31]

Answer:

see explanation

Step-by-step explanation:

Using cross- products, that is

$\frac{a}{b}$ = $\frac{c}{d}$ then ad = bc

Given the ratios

$\frac{4}{14}$ and $\frac{6}{21}$

Then equating and using cross- products

If both sides equate then the ratios are equivalent

$\frac{4}{14}$ = $\frac{6}{21}$ , then

4 × 21 = 6 × 14 ⇒ 84 = 84

Both sides are equal thus the ratios are equivalent

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3 years ago

Find the amount on 800 for one year at 10%

Rudiy27

Answer:

80

Step-by-step explanation:

You mean the "interest on"

I=800×.1×1=80

7 0

2 years ago

Read 2 more answers

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

So

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

So

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

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3 years ago

Help please...I'll do anything...

Sveta_85 [38]

Answer:

Step-by-step explanation:

Here is a formula that can help:

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2 years ago

Iron has a density of 7.9 g/cm³. Gold has a density of 19.3 g/cm³.

alexandr402 [8]

Density = m/v
3.86kg=3860g
d= 3860/200
= 19.3g/cm^3
therefore it is gold.

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2 years ago