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Schach [20]
3 years ago
13

Ms Clark bought 9 yards of fabric. She used it to make 13 identical scarves. How many yards of fabric did she use to make each s

carf?
Mathematics
1 answer:
Alona [7]3 years ago
6 0

Answer:

9/13 or 0.69 yards

Step-by-step explanation:

To find the amount of fabric per scarves, divide the number of yards by the number of scarves.

9/ 13 = 0.69 yards per 1 scarf

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Add parentheses 10+9×3-1×2 equal greater than 75
vitfil [10]
(10 + 9) x (3 - 1) x 2 = +75
19 x 2 x 2
76
76 > 75


5 0
3 years ago
Can someone help me with these functions
ryzh [129]

Answer:

Function 1:

The starting point is (0,0.5)

As x increases, y increases

Function 2:

The starting point is (0,3)

As x increases, y decreases

Step-by-step explanation:

In order to find the starting point, we need to plug in x=0.

y=0.5+3(0)\\\\y=0.5

y=3(0.5)^0\\\\y=3(1)\\\\y=3

As we plug in increasing numbers into function#1, the y-value increases

As we plug in increasing numbers into function #2, the y-value is decreasing

3 0
3 years ago
Inverse laplace of [(1/s^2)-(48/s^5)]
Katen [24]
**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform F(s) and G(s), then \mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}

Given that \dfrac{1}{s^2} = \dfrac{1!}{s^2} and -\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}

From Table of Laplace Transform, you have \mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}} and hence \mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}.

Hope this helps...
7 0
3 years ago
A book seller gains 30% on the cost price by selling a book for $130.Calculate the cost price of the book.​
zlopas [31]

Answer:

Let the cost price be x

  • Selling price, S.P. = 130
  • Gain % = 30%

\rm{C.P. = \dfrac{S.P. \times 100}{100+ gain \% }}

\rm{C.P. = \dfrac{130 \times 100}{100+30}}

\rm{ C.P. = \dfrac{130}{30} }

\large{\boxed{\rm{ C.P. =  \dfrac{13}{3}}}}

6 0
2 years ago
-<br> The sum of 2 and x is at least - 19.
In-s [12.5K]

2 + x = -19 <=> x = -19 -2 = -21

4 0
2 years ago
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