First, find what percentage of students had 3 or more by adding up your known percents:
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:

This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is
135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is
33 students.
By using a graphing calculator, the solutions are:
(-3, 4) and (1, 0)
Answer:
thank you hahahahahahaha <3
Answer:
f(x) = (x + 6)² - 29
Step-by-step explanation:
Given
f(x) = x² + 12x + 7
To complete the square
add/subtract ( half the coefficient of the x- term )² to x² + 12x
x² + 2(6)x + 36 - 36 + 7
= (x + 6)² - 29, thus
f(x) = (x + 6)² - 29
72.5+32.7= 105.2
Triangle angles have to equal 180
180-105.2= 74.8
Third angle= 74.8 degrees