1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AveGali [126]
3 years ago
12

What is x in 5x +(3-1)=12

Mathematics
1 answer:
olga2289 [7]3 years ago
5 0

Answer:

x=2

Step-by-step explanation:

5x +(3-1) =12

5x +2 =12

5x =12-2

5x =10

x =10÷5

x =2

You might be interested in
Suzanne owns a small business that employs 555 other people. Suzanne makes \$100{,}000$100,000dollar sign, 100, comma, 000 per y
zalisa [80]

Answer:

16

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Two airlines offer special group rates to your school’s Spanish Club for a trip to Mexico City. Mexican Air airline offers a rou
Finger [1]

Answer:

a. The Mexican Airline offers a better deal for 9 students to travel.  

b. 10 students

Step-by-step explanation:

a. The Mexican Air airline offers a round trip airfare of $250 per person.

So, for 9 students the fare will be total $(250 × 9) = $2250

Now, the Fiesta airline offers a round trip airfare of $150 per person if the club agrees to pay a one-time group rate processing fee of $1000.

So, for 9 students the total fare will be = $[1000 + (150 × 9)] =$2350.

Therefore, the Mexican Airline offers a better deal for 9 students to travel.  (Answer)

b. Let for x students both the airline offers the same total costs.

Then we can write  

250x = 1000 + 150x {From the conditions given}

⇒ 100x = 1000

⇒ x = 10

So, if the number of students is 10, then only both the airlines will take same fare. (Answer)

8 0
4 years ago
Can someone help me please
Neporo4naja [7]

If Deliah does jumping jacks at a constant rate, this means that she does them at the same pace or you could say that she does the same amount of jumping jacks in a specified amount of time, ie. if you counted how many jumping jacks she did in one minute, it would be same as how many she would complete in the next minute, and the next, and so on.

Now given that she does 184 jumping jacks in four minutes, and she has kept a constant pace throughout, to find out how many she does each minute, we simply need to divide the number of jumping jacks she does in 4 minutes by 4. Thus:

Jumping jacks in 1 minute = Jumping jacks in 4 minutes / 4

= 184 / 4

= 46

Thus, Deliah can do 46 jumping jacks per minute.

5 0
4 years ago
2. Based on the table below, determine the exponential function being used. Use x as your variable. Then, evaluate this expressi
Ostrovityanka [42]

Answer:

y=5^{x}\\y=5^{7}=78125

Step-by-step explanation:

y = a^{x}, a=5\\y=5^{x}\\y=5^{0}=1\\y=5^{1}=5\\y=5^{2}=25\\y=5^{3}=125\\and\\y=5^{7} = 78125

4 0
3 years ago
Ryan earn $376 by working 4 days. If he earned the same amount each day, how much he earn working 5 days?
Over [174]
$469.


376/4 = 94.

Then add that too 346

94 + 346 = 469

3 0
4 years ago
Read 2 more answers
Other questions:
  • Difference between a bowling ball and a baseball
    13·2 answers
  • Tissues of living organisms consist primarily of organic compounds; that is, they contain carbon molecules known as proteins, ca
    6·2 answers
  • What is the value of ¡97 - i?
    14·1 answer
  • How would making a table help you to find the number of minutes it took Sam to cut the sheet metal into 8 pieces
    6·1 answer
  • What is the value of k in y = kx, if y = 12 when x = 24?
    5·2 answers
  • Welcome to baldys basics answer below :P
    10·2 answers
  • 10.
    10·1 answer
  • A bag can hold 1 1/2pounds of flour. if Mimi has 7 1/2pounds of flour, then how many bags of flour can Mimi make?
    7·2 answers
  • Please help i will mark brainliest!!! i would appreciate it sm ​
    12·1 answer
  • If the die were to be rolled 6000 times, would we expect to obtain exactly 1000 '2's? explain your answer.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!